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Anvisha [2.4K]
3 years ago
10

The amount of time needed to complete a certain roadtrip, t, varies inversely with the speed of a vehicle, s. At a speed of 52 m

iles per hour, the trip will be complete in 12 hours. How many hours would it take at a speed of 48 miles per hour?
Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

The time it will take is 13 hours

Step-by-step explanation:

From the given statement, we can generate the following inverse proportion relationship between t and s

t ∝ 1/s

t = \frac{k}{s} \\\\where;\\\\k \ is \ constant\\\\k = t_1s_1 = t_2s_2 \\\\t_2 = \frac{t_1s_1}{s_2} \\\\t_2 = \frac{12 \times 52}{48} \\\\t_2 = 13 \ hours

The time it will take is 13 hours

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Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

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This means that p = 0.1

Four travelers who have made hotel reservations in this study.

This means that n = 4

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561

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P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

X = 0 has the highest probability, which means that 0 is the most likely value for X.

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3 years ago
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