Start with the parentheses
Answer:
C. (-4x^2)+2xy^2+[10x^2y+(-4x^2y)
Step-by-step explanation:
A. [9-4x2) + (-4x2y) + 10x2y] + 2xy2 : in this polynomial the first term is not a like term, then this is incorrect.
B. 10x2y + 2xy2 + [(-4x2) + (-4x2y)] : in this polynomial, the terms that are grouped, are not like terms, then is incorrect.
C. (-4x2) + 2xy2 + [10x2y + (-4x2y)] ; This polynomial is the right answer because the like terms are grouped.
D. [10x2y + 2xy2 + (-4x2y)] + (-4x2): This polynomial is incorrect because one of the terms that are grouped is not a like term.
we can use MS excel to plot the given data and check whether the graph's trendline has an R-squared of 1. The graph does not fit into a line but fits into an exponential function. The trendline's equation is equal to y = 4e^1.3863x where R squared is equal to 1
Answer:
175/48 or 3.64
Step-by-step explanation:
■ Refer to the attachment.
Hope it helps ⚜
Answer:
Madam Gazelle
Step-by-step explanation:
