Question on image. (calculus)

1 answer:

5 0

Answer:

Step-by-step explanation:

$\tan^{-1}(\frac{a}{b})}$ is the angle on the right, so

$\cos[\tan^{-1}(\frac{a}{b})}]=\frac{b}{\sqrt{a^2+b^2}}$

That is D

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