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klasskru [66]
4 years ago
10

What is the Ksp of nickel(II) sulfide if the equilibrium concentrations of Ni2+ and S2− in a saturated solution of NiS are each

1 × 10−10M?
Chemistry
1 answer:
Ludmilka [50]4 years ago
7 0
Dont know if its right but :/ <span>NiS <---> Ni+2 + S-2 </span><span>Ksp = [Ni+2] * [S-2] = (9.6E=11)^2 = 9.22E-21</span>
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Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

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V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

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