Answer:
i would say 10, so the anser is A.
Explanation:
because there are the same number of protons and electrons, therefore for a regular O, you are supposed to have only 8 protons, but it is charged, thus, whatever the charge is will be taken into consideration into how much the proton and electron doe it have. Thus, for this case, it has 10, because the charge is negative and you have 8 electron plus 2 = 10.
C.) Electrical Signals are not used <span>to locate underground oil reserves
Hope this helps!</span>
Answer:
Explanation:
From the information given:
oxidation of oxidized solution takes place at 950° C
For wet oxidation:
The linear and parabolic coefficient can be computed as:
![\dfrac{B}{B/A} = D_o \ exp \Big [\dfrac{-\varepsilon a}{k_BT} \Big]](https://tex.z-dn.net/?f=%5Cdfrac%7BB%7D%7BB%2FA%7D%20%3D%20D_o%20%5C%20exp%20%5CBig%20%5B%5Cdfrac%7B-%5Cvarepsilon%20a%7D%7Bk_BT%7D%20%5CBig%5D)
Using
and
values obtained from the graph:
Thus;
![\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr](https://tex.z-dn.net/?f=%5Cdfrac%7BB%7D%7BA%7D%20%3D%201.63%20%5Ctimes%2010%5E8%20exp%20%5CBig%20%5B%20%5Cdfrac%7B-2.05%7D%7B8.617%20%5Ctimes%2010%5E%7B_-5%7D%5Ctimes%201173%7D%5CBig%5D%20%5C%5C%20%5C%5C%20%3D%200.2535%20%5C%20%5C%20%5Cmu%20m%2Fhr)
![B= 386 \ exp \Big [-\dfrac{0.78}{8.617 \times 10^{-3} \times 1173} \Big] \\ \\ = 0.1719 \ \mu m^2/hr](https://tex.z-dn.net/?f=B%3D%20386%20%5C%20%20exp%20%5CBig%20%5B-%5Cdfrac%7B0.78%7D%7B8.617%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%201173%7D%20%5CBig%5D%20%5C%5C%20%5C%5C%20%20%3D%200.1719%20%5C%20%5Cmu%20m%5E2%2Fhr)
So, the initial time required to grow oxidation is expressed as:


∴


NOW;







Thus; since we will consider the positive sign, the initial thickness
is ;
≅ 0.261 μm
Answer:
The plasmodial slime molds are the kind of protist that can live in groups in which different individuals perform different jobs. Some kinds of bacterial cell walls also have other functions.