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Alex73 [517]
3 years ago
13

How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin?

Chemistry
2 answers:
TiliK225 [7]3 years ago
5 0

<u>Answer:</u> The moles of ethylene gas that can react is 0.212 moles

<u>Explanation:</u>

To calculate the moles of oxygen gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.2 atm  

V = Volume of the gas = 12.9 L

T = Temperature of the gas = 297 K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

1.2atm\times 12.9L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 297K\\\\n=\frac{1.2\times 12.9}{0.0821\times 297}=0.635mol

For the given chemical equation:

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(g)

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 1 mole of ethylene gas

So, 0.635 moles of oxygen gas will react with = \frac{1}{3}\times 0.635=0.212mol of ethylene gas

Hence, the moles of ethylene gas that can react is 0.212 moles

Elena-2011 [213]3 years ago
4 0
3 moles of oxygen will react with 1 mole of ethylene. Convert 12.9 L of oxygen to x moles of oxygen, then divide by three.
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