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Sveta_85 [38]
3 years ago
7

Niech ktoś pomoże ! a)5 2\7 +1 3\7 -1\7= b)4 5\9 -2 4\9 +3 2\9= c)2 2\3 -(1 4\9 +2 3\9=

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

A) 6 4/7

B) 5 3/9

C) 6 6/3

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Please help this is very important
alexandr1967 [171]

Answer:

Here's what I get.

Step-by-step explanation:

1. Rotate 180° about origin

The formula for rotation of a point (x,y) by an angle θ about the origin is  

x' = xcosθ  -  ysinθ

y' = ycosθ + xsinθ

If θ = 180°, sinθ = 0 and cosθ = -1, and the formula becomes

x' =   -x

y' =  -y

The rule is then (x, y) ⟶ (-x, -y).

H: (-3, -5) ⟶ (3, 5)

J: (-5, -3) ⟶ (5, 3)

Q: (0, -1) ⟶ (0, 1)  

The vertices of H'J'Q' are (3, 5), (5, 3), and (0, 1).

2. Rotation 90° counterclockwise about origin

cos90°  = 0 and sin90° = 1

x' = xcos90°  -  ysin90° = -y

y' = ycos90° + xsin90° =  x

The rule is then (x, y) ⟶ (-y, x).

B: (4, 5) ⟶ (-5, 4)

L: (5, 0) ⟶ (0, 5)

S: (2, 2) ⟶ (-2, 2)  

The vertices of B'L'S' are (-5, 4), (0, 5), and (-2, 2).

3. Rotation 90° clockwise about origin

cos(-90°) = 0 and sin(-90°) = -1

x' = xcos(-90°)  -  ysin(-90°) =  y

y' = ycos(-90°) + xsin(-90°) =  -x

The rule is then (x, y) ⟶ (y, -x).

F: (1, -5) ⟶ (-5, -1)

H: (-2, -3) ⟶ (-3, 2)

U: (-4, -5) ⟶ (-5, 4)  

The vertices of F'H'U' are (-5, -1), (-3, -2), and (-5, 4).

4. Rotate 180° about origin

The rule is (x, y) ⟶ (-x, -y).

J: (1, -1) ⟶ (-1, 1)

V: (2, 0) ⟶ (-2, 0)

Y: (5, -3) ⟶ (-5, 3)

R: (4, -3) ⟶ (-4, 3)  

The vertices of J'V'Y'R' are (-1, 1), (-2, 0), (-5, 3), and (-4, 3).

The figures below show your shapes before and after the rotations.

7 0
3 years ago
What is the measure of arc FLI?
leva [86]

Answer:

140

Step-by-step explanation:

By inscribed angles, arc FPI = 2<FLI = 2*110 = 220. Since the entire arc of a circle is 360, we know that arc FLI + arc FPI = 360. Solving, we get arc FLI = 360 - 220 = 140.

I hope this helps!

3 0
2 years ago
Round 1149 to the nearest thousand.
zysi [14]
1150, i’m pretty sure that’s it!
4 0
3 years ago
A six-foot-tall person is standing next to a flagpole. The person is casting a shadow 1 1/2 feet in length, while the flagpole i
lara31 [8.8K]

Answer: 20 ft

This problem can be solved by the Thales’s theorem, which states:

<em>Two triangles are similar when they have equal angles and proportional sides  </em>

It should be noted that to apply Thales' Theorem, it is necessary to establish <u>the two triangles are similar</u>, that is, that t<u>hey have the corresponding angles equal or that their sides are proportional to each other.  </u>

<u />

Now, if we measure the shadow of the flagpole and the shadow of the person, <u>at the same moment</u>, we can use the first Thales' Theorem to calculate the height of the flagpole, knowing the height of the person.

In this case we have two similar triangles (Figure attached) where H is the height of the flagpole, h=6 ft is the height of the person, A=5 ft is the length of the shadow of the flagpole and a=1\frac{1}{2}=1.5 ft is the length of the shadow of the person.

Having this clear, we can write the following relation with both similar triangles:

\frac{H}{h}=\frac{A}{a}   (1)

We know all these lengths except H, which is the value we want to to find.  

So, in order to approach this problem we have to find H from equation (1):  

H=\frac{A}{a}h  

H=\frac{5 ft}{1.5 ft}(6 ft)  

Then:

H=20 ft >>>>>This is the height of the flagpole

4 0
3 years ago
1. Jordan's washing machine is broken. Since her machine is pretty old, she doesn't want to spend more than $100
ahrayia [7]

Answer:

I think it would be D

Step-by-step explanation:

20 x 3 =  60      60+35= 95          20/4 = 5  

4 0
3 years ago
Read 2 more answers
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