The set of counting numbers is

In the figure, three line segments cross at a common point. Angle A is 45°, and angle E is 85°. What is the measurement of angle

katen-ka-za [31]

Answer: Measure angle H = 42°

Step-by-step explanation:

"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"

In given we have,

angle E is an exterior angle to triangle DFH

The two non-adjacent angles to angle E are angles D and H

Based on the above rule,

measure angle E = measure angle D + measure angle H

We are given this:

angle E = 87°

angle D = 45°

Substitute with the givens in the above rule and solve for the measure of angle H as follows:

angle E = angle D + angle H

87° = 45° + measure angle H

measure angle H = 87° - 45°

measure angle H = 42°

Hope this helped!

5 0

3 years ago

Use each integer only once. You must have each row, column, and diagonal adding up to the magic sum.

Grace [21]

For question number 3
-7, 7, 6, -4,
4, -2, -1, 1
0, 2, 3, -3,
5, -5, -6, 8

For question number 4:
-4, 1, -10, 3,
-9, 2, -3, 0,
5, -8, -1, -6,
-2, -5, 4, -7

8 0

2 years ago

Read 2 more answers

3x+2=11,what does this equal to I’m confused

kicyunya [14]

Answer:

3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Need help, really not good with anything in math

Anettt [7]

Answer:

D. 40.

Step-by-step explanation:

Find the reciprocal of 1/40:

1/40
= 40/1
= 40.

That's really it.

Your answer is 40 (D).

5 0

2 years ago

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 33% of all homeowners are ins

Lina20 [59]

Answer:

(a) The probability mass function of X is:

$P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...$

(b) The most likely value for X is 1.32.

(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.

Step-by-step explanation:

The random variable X is defined as the number among the four homeowners who have earthquake insurance.

The probability that a homeowner has earthquake insurance is, p = 0.33.

The random sample of homeowners selected is, n = 4.

The event of a homeowner having an earthquake insurance is independent of the other three homeowners.

(a)

All the statements above clearly indicate that the random variable X follows a Binomial distribution with parameters n = 4 and p = 0.33.

The probability mass function of X is:

$P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...$

(b)

The most likely value of a random variable is the expected value.

The expected value of a Binomial random variable is:

$E(X)=np$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.33\\=1.32$

Thus, the most likely value for X is 1.32.

(c)

Compute the probability that at least two of the four selected have earthquake insurance as follows:

P (X ≥ 2) = 1 - P (X < 2)

= 1 - P (X = 0) - P (X = 1)

$=1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015$

Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.

3 0

3 years ago