The set of counting numbers is

Suppose a store has 100 light bulbs in stock. Assume 40 light bulbs are from Distributor A and the remainder of the light bulbs

Alborosie

15 percent i believe

5 0

3 years ago

List at least 4 attributes that are shared by all of the shapes in the rectangle group

inessss [21]

Answer:

All of the figures have 4 sides and 4 vertices

They have opposite sides parallel and congruent.

They have four right angles.

They also have perpendicular line segments.

Step-by-step explanation:

Hope this helps!!!

7 0

3 years ago

Rachel's birthday party will cost $18 if she invites 6 guests. What is the unit rate?

Whitepunk [10]

Answer:

3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write y=-1/4x-6 in standard form using integers.

juin [17]

The standard form of a linear equation is Ax + By = C.

Y = -1/4 x – 6
Multiply the whole equation by 4
4( y = -1/4 x – 6) 4y = -x – 24
Transpose -x to the other side of the eqution to obtain standard form
X + 4y = -24

7 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

3 years ago