Answer:
60 square units
Step-by-step explanation:
We can use Pythagoras to solve this as appropriately projecting lines from any point will form a triangle. The vertical and horizontal lengths of which can be read of from the axis.
The distance between two points is √
(
x
1
−
x
2
)
2
+
(
y
1
−
y
2
)
2
Let the distance between two points be
d
i
Distance between points A and B
d
1
=
√
[
3
−
(
−
3
)
]
2
+
[
7
−
5
]
2
d
1
=
√ 36
+
4
=
√
2
2
×
10
=
2
√
10
Distance between points B and C
d2
=
√
[
6
−
3
]
2
+
[
7
−
(
−
2
)
]
2
d
2
=
√
9+
81
=
√
3
2
×
10
=
3
√
10
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Area =
d
1
×
d
2
=
2
√
10
×
3
√
10
=
60
YW :>
Plug in -8 for x to get 8(-8)+8y=-48. then you have -64+8y=-48. add 64 to the right side of the equation to get 16. now you have 8y=16. divide by 8 to have the variable by itself so y=2.
Use the Pythagorean Theorem. a = b = 5 so
5^2 + 5^2 = c^2
25 + 25 = c^2
50 = c^2
c = 5
= 7.071
You can multiply both sides by a number that will get rid of the denominators. For ex. you can multiply the first equation by 12 because 4 and 3 both go into 12 evenly. MAKE SURE YOU MULTIPLY THE OTHER SIDE BY 12 AS WELL! Therefore, 12(x/4) - 12(y/3) = 12(1), or 3x - 4y = 12
