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ad-work [718]
3 years ago
11

Can someone help with this please?

Mathematics
2 answers:
ipn [44]3 years ago
3 0

7^2=7\cdot7=49\\\\8^2=8\cdot8=64\\\\\sqrt{49}

alex41 [277]3 years ago
3 0

Answer:

Its 52

Step-by-step explanation:

the square root of 52 is 7.2

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When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

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We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

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If you multiply this out you will get the exact expression we were given. This means that:
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We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


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