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3 years ago

What is the slope?????????

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

To find slope, divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points,hope this helps you (:

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6r-2(r+8)=11<br> Solve equation

pav-90 [236]

$6r-2(r+8)=11\ \ \ \ |\text{use distributive property}\\\\6r-2(r)-2(8)=11\\\\6r-2r-16=11\ \ \ \ \ |+16\\\\4r=27\ \ \ \ \ |:4\\\\r=6.75$

4 0

3 years ago

Please answer ASAP<br> Thank you so much!!!!

anzhelika [568]

Answer:

See below

Step-by-step explanation:

Grade is slope = rise / run

a) horizontal distance 1400 ft (run) vertical distance = 40 ft (rise)

40 / 1400 = 2.85%

b) rise / run = 805.58 / 13780 = 5.84%

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1 year ago

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mr Goodwill [35]

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7 0

3 years ago

Please help, I dont know how to do this

Mrrafil [7]

Answer:

$\frac{y-2}{4}$

Step-by-step explanation:

Let's start by factoring everything:

$\dfrac{\frac{y^2+y}{y^2-2y}}{\frac{4y+4}{y^2-4y+4}}=$

$\dfrac{\frac{y(y+1)}{y(y-2)}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, you can cancel out some terms:

$\dfrac{\frac{y+1}{y-2}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, when you divide a fraction by another fraction, that is the same as multiplying the first fraction by the reciprocal of the second one:

$\frac{y+1}{y-2}\cdot \frac{(y-2)^2)}{4(y+1)}=$

$\frac{y-2}{4}$

Hope this helps!

4 0

3 years ago

The path of a softball thrown by maddie forms a parabola wirh the equation y=-3/2401(x-49)^2+8.5 how far does the ball travel ve

ExtremeBDS [4]

Answer:

The distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

Step-by-step explanation:

The given parabolic equation is

$y=-\frac{3}{2401}(x-49)^2+8.5$

Where, h is height of ball after covering x distance horizontally.

Put x=0, to find initial height of the ball.

$y=-\frac{3}{2401}(0-49)^2+8.5$

$y=-3+8.5$

$y=5.5$

Put y=5.5 in the given equation and find the values of x at which the height of ball is 5.5.

$5.5=-\frac{3}{2401}(x-49)^2+8.5$

$\frac{3}{2401}(x-49)^2=-5.5+8.5$

$\frac{3}{2401}(x-49)^2=3$

$(x-49)^2=2401$

Take square root both sides.

$x-49=\pm 49$

$x=\pm 49+49$

$x=0,98$

The height of ball is 5.5 at x=0 and x=98.

Therefore distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

7 0

3 years ago