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3 years ago

What is the slope?????????

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

To find slope, divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points,hope this helps you (:

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Which value of x makes the equation true? x – 5.1 = –7.6

ASHA 777 [7]

X-5.1 = -7.6
+5.1 +5.1
X= -2.5

7 0

3 years ago

Read 2 more answers

Which of the following could be the equation of the graph shown below? Check all that apply.

Mashutka [201]

Answer:

y = -2x + 5

Х-y= 9

2x + y = 4

y = 5

lmk if incorrect, please give brainliest

8 0

3 years ago

Four sets of three squared

yKpoI14uk [10]

Answer:

$4^3$

Step-by-step explanation:

Four sets of three Squared

To start, you will need to get the set(base number) and get the exponent 3 and put it on the top.

$4^3$

Hope this helps!

8 0

3 years ago

Please help it's the SLOPE

Maksim231197 [3]

Answer:

$- \frac{4}{5}$

Step-by-step explanation:

Please see the attached picture.

$slope \\ = \frac{1 - ( - 3)}{ - 3 - 2} \\ = \frac{1 + 3}{ - 5} \\ = - \frac{4}{5}$

☆In the gradient formula,

(x1, y1) is the first coordinate and (x2, y2) is the second coordinate.

3 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago