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3 years ago

2. A rectangular prism has e flat surfaces . 3, A cone h as -flat surface. A cube has 요 flat surfaces.

Mathematics

1 answer:

alisha [4.7K]3 years ago

6 0

All correct except that
cube has 6 flat surfaces, it's like a rectagular prism, but special

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You buy 20 fluid ounces of shampoo for $4.40 or 24 fluid ounces for $4.80. Which is the better buy? P.S. Can u please show me th

yKpoI14uk [10]

To make this easier lets convert dollars into cents so : 440 cents gives 24 , 440÷20=22 cents for each ounce
the other deal : 480÷24=20 cents for each ounce This one is cheaper per ounce this one is better
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7 0

3 years ago

Read 2 more answers

Label each of the triangles illustrated below

AVprozaik [17]

A: Equilateral
B: Obtuse
C: Obtuse
D: Right
E: Obtuse
F: Acute

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3 years ago

B is the midpoint of AC. C is the midpoint of AD. Find the coordinates of B and D given the coordinates of A (-2,5) and the coor

GalinKa [24]

B= (3,6) and D= (18,9)

Step-by-step explanation:

To find the midpoint of two given points add X1 and X2 together, then divide by 2 to get the X value of the midpoint and do the same thing for the Y value. That will get you B. From there you can see to get from point A to point C you add 10 to the x value and add 2 to the y value. Because C is the midpoint just double what you had to add to get point D (add 20 to x and add 4 to y)

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3 years ago

A cylinder has a volume of 75 cubic centimeters. What is the volume of a sphere with the same height and radius?

bagirrra123 [75]

The sphere and the cylinder have the same heightbecause of this the height of the cylinder is equal to the diameter of the spherethe diameter of the sphere is 2*7=14 cm, so the height of the cylinder is also 14 cmthe radius of the cylinder is 7 cmV=∏*r^2*hV=3.14159*7^2*14V=3.14159*49*14V=3.14159*686V=2155.13074 cubic cm, or...V=(22/7)(7^2)(14) (22/7 is an approximation for pi)V=(22/7)(49)(14)V=(22)(7)(14)V=(22)(98)V=2156 cubic cm

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3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

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3 years ago