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Otrada [13]
3 years ago
14

Create your own real world problem that involves designing a 2D shape.

Mathematics
2 answers:
andrey2020 [161]3 years ago
8 0

Answer:

A square with 20ft sides is put on the moon

Step-by-step explanation:

what is perimeter

sides = s

s x 4/4 = 20

s = 20

s x 4 = 80

Greeley [361]3 years ago
4 0
Sides =s that one of ur answers
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Can someone help me please ASAP
zmey [24]

Answer:

<h2>140°</h2>

solution,

Let <DEF= x°

<CDE= 2x°

<BAF= 90°

The sum of interior angle of hexagon= 720°

<A + <B + <C + <D + <E +<F = 720°

90 + 145 + 115 + 2x + x + 160 = 720 \\ 510 + 3x = 720 \\3x + 510 = 720 \\ 3x + 510 - 510 = 720 - 510 \\ 3x = 210 \\  \frac{3x}{x}  =  \frac{210}{3}  \\ x = 70 \: degree

Again,

< \: cde = 2x \\  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  = 2 \times 70 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 140 \: degree

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
What is the length of the altitude of the equilateral triangle below?
balandron [24]

\bf \textit{height or altitude of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2}~~ \begin{cases} s=\stackrel{length~of}{a~side}\\ \cline{1-1} s=8\sqrt{3} \end{cases}\implies h=\cfrac{8\sqrt{3}\cdot \sqrt{3}}{2}\implies h=\cfrac{8\sqrt{3^2}}{2} \\\\\\ h=4\cdot 3\implies h=12

3 0
3 years ago
A line has the equation -5x -14y +168 = 0
valkas [14]

Answer:

y = -5/14x + 12

Step-by-step explanation:

add 14y to both sides to isolate variables and divide everything by 14 to get 1y and boom

6 0
2 years ago
If the diameter of a circle is 12 feet, then the radius of the circle is
zhuklara [117]
The radius is 6 feet. The radius will always be half of whatever the diameter is
5 0
3 years ago
Read 2 more answers
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