We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Step-by-step explanation:
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Answer:

Step-by-step explanation:
Given

Recursive: 
Required
Determine the formula
Substitute 2 for n to determine 


Substitute 


Next is to determine the common difference, d;



The nth term of an arithmetic sequence is calculated as

Substitute
and 


Hence, the nth term of the sequence can be calculated using
Answer: 0.500
Step-by-step explanation:
Given : A normal distribution has a mean
of 10 and a standard deviation
of 1.
Let x be a random variable that represents numbers .
The probability of selecting a number that is at most 10 will be

As the area occupied by standard normal curve less than equal to 0 = 0.500
So, required probability = 0.500