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Olenka [21]
3 years ago
13

Pyramid A is a right square pyramid with a height of 133m and a square base with a perimeter of 492m. Pyramid B has a square bas

e with a perimeter of 592m and a height of 247m. Which pyramid has the greater volume and by how many times as​ great?
Mathematics
1 answer:
erica [24]3 years ago
3 0

9514 1404 393

Answer:

  Pyramid B is 2.6888 times the volume of pyramid A

Step-by-step explanation:

The volume is proportional to the height, and to the square of the linear measure of the base.

Then the ratio of volumes will be ...

  B/A = (592²·247)/(492²·133) = 86564608/32194512 ≈ 2.6888

Pyramid B has the greater volume by a factor of about 2.6888.

_____

<em>Additional comment</em>

The actual volumes in cubic meters will be 1/48 of the numbers we used in the ratio above.

If you recall that the side length is related to the perimeter by ...

  P = 4s   ⇒   s = P/4

and the volume is ...

  V = 1/3s²h

Then you have ...

  V = 1/3(P/4)²h = 1/48·P²h . . . . . . P²h is the number we used above

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Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

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Step-by-step explanation:

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