Answer:
600 and 3
Step-by-step explanation:
Answer:
₹165.79
Step-by-step explanation:
Given:-
No. of electric bulbs = 1000
cost of each electric bulb = ₹ 150
No. of bulbs broken = 50
Selling price of each bulb = x
Profit percentage = 5%
To Find:-
The selling price of each bulb.
Solution:-
Cost price of 1000 electric bulbs,
= 1000 × ₹150
= ₹1,50,000
5% profit on the total cost price,
= {5}/{100}× ₹150000
= ₹7500
Total selling price = ₹157500
No. of bulbs remaining = 950
Therefore, selling price of each bulb,
= {₹157500}/{950}
= ₹165.79
Therefore,
Selling price of each bulb = ₹165.79
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
