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Anastaziya [24]
3 years ago
11

What is the answer to this question

Mathematics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

56

Step-by-step explanation:

7 (2)^3

We do this according to PEMDAS

The Parentheses here are do indicate what is in the exponent

We do the Exponent first

2^3 = 2*2*2 = 8

7(8)

There is an implied multiplication here

7*8

Now we do the multiplication

56

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translate the sentence into an equation. the product of 8 and a number increased by 4 is 60.a. 8y 4 = 60b. 4y 8 = 56c. 8 ÷ y 4 =
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"T<span>he product of 8 and a number increased by 4" may be understood by 2 ways:
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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

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substitute

A2=\pi (3)^{2}/2

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The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

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