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weeeeeb [17]
3 years ago
5

음what is 1/8 divided by 3/4 equal ​

Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

1/6

Step-by-step explanation:

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Helppppppppppp meeeee​
tatuchka [14]

Answer:

y = -2x + 3

Step-by-step explanation:

Let's just put the three points together.

(-1, 5) (-4, 11) (-7, 17)

First, let's find the slope with y2 - y1/x2 - x1

Plug in using (-1, 5) and (-4, 11)

11 - 5/-4 + 1 = 6/-3 (simplify)

-2 is the slope

Now plug in (-7, 17) in the equation to get b or the y-intercept)

y = mx + b

17 = -2(-7) + b

17 = 14 + b (subtract 14 on both sides)

3 = b

y = -2x + 3

8 0
3 years ago
6 clients are throwing a party. Each cake serves 24 servings and has a party of 70 +3staff how many cakes are needed?
Airida [17]
4 cakes are needed fjfnccnfn
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3 years ago
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Which graph shows the solution set for -5/2x -3<2 ​
ollegr [7]

Answer:

Is there supposed to be a photo? Or attachment?

Step-by-step explanation:

5 0
2 years ago
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Michael found a jake at the bank he said that he went there every 45 days and Michael says he went every 30 days .when will they
Ahat [919]
They will see each other every 30 days but won't every 15 days
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3 years ago
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State the domain and range of both the function and the inverse function. f(x) = 8 x + 8 f -1(x) = Domain of f(x): Range of f(x)
Katena32 [7]

Answer:

f^{-1}(x) = \frac{x+8}{8}

Domain of f(x): All real values.

Range of f(x): All real values.

Domain of f -1(x): All real values.

Range of f -1(x): All real values

Step-by-step explanation:

We are given the following function:

f(x) = 8x + 8

Since it is a line, we have that both the domain is the range is the real set.

Inverse function:

The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function.

Finding the inverse function:

Exchange x and y in the original function, and isolate y. So

Original

y = 8x + 8

Exchanging:

x = 8y - 8

Isolating y:

8y = x + 8

y = \frac{x+8}{8}

f^{-1}(x) = \frac{x+8}{8}

5 0
2 years ago
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