Hi picture is up there thank you so much for the help.

The expression 3(x-9) is equivalent to 3(x)+9. 3(x)+3(9). 3(x) – 9. 3(x) – 3(9).

sukhopar [10]

Answer:

3(x) – 3(9)

Step-by-step explanation:

3(x-9)

Distribute the 3 to each term in the parentheses

3*x -3*9

3x -27

3 0

2 years ago

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Write a proof for the conjecture using the contrapositive. If 5x + 7 = -13, then x = -4.

KonstantinChe [14]

Answer:

ans x=4

Step-by-step explanation:

5x + 7 = -13
5x = -13 -7
5x= -20
x = -20/5
x = -4
so the answer is x= -4

3 0

3 years ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

so

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

case A) point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

case B) point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

case C) point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

case D) point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

case E) point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

case F) point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

the answer is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

3 years ago

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If a rocking horse has the weight limit of 60 pounds what is 95% of the limit

Eduardwww [97]

Answer:

57 pounds

Step-by-step explanation:

I Turned 95% into a decimal, Hmm- Which would be 0.95, then I multiplied it by 60 pounds, which equals 57 pounds.

- CAT NOIR

6 0

3 years ago

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a film canister in the shape of a cylinder has a height of 8 centimeters and a volume of the film canister. write an equation fo

uranmaximum [27]

Answer:

Part a) The equation for the volume of the film canister is

$32\pi=\pi r^{2}(8)$

Part b) The radius of the film canister is $2\ cm$

Step-by-step explanation:

The complete question is

A film canister in the shape of a cylinder has a height of 8 centimeters and a volume of 32π cubic centimeters.

a. Write an equation for the volume of the film canister.

b. What is the radius of the film canister?

Part a) Write an equation for the volume of the film canister

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

where

r is the radius of the circular base

h is the height of the cylinder

we have

$V=32\pi\ cm^3$

$h=8\ cm$

substitute

$32\pi=\pi r^{2}(8)$ ----> equation for the volume of the film canister

Part b) What is the radius of the film canister?

we have

$32\pi=\pi r^{2}(8)$

$32\pi=8\pi r^{2}$

Simplify

Divide by 8π both sides

$4=r^{2}$

square root both sides

$r=2\ cm$

8 0

3 years ago