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LekaFEV [45]
3 years ago
13

Help me please ASAP

Mathematics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

Srry but i can't see the numbers in the corner...it's kinda blurry..give a question again then zoom it...

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I rlly need help with thins question asap​
Gnesinka [82]

Answer:

The 3 one is 2 and the forth one is 10

Step-by-step explanation:

i did the math

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3 years ago
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Which of the following individuals best illustrates an extrinsic religious motivation?
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<span>Rhonda who attends religious services in order to promote her business contacts</span>
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A random sample of 30 households was selected as part of a study on electricity usage, and the number of kilowatt-hours (kWh) wa
grin007 [14]

Answer:

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 30 - 1 = 29

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.462

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.462\frac{91.5}{\sqrt{30}} = 41.13

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 375 - 41.13 = 333.87 kWh

The upper end of the interval is the sample mean added to M. So it is 375 + 41.13 = 416.13 kWh

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

6 0
3 years ago
What two numbers multiply to 40 and add to -6
Darya [45]

Answer: Nothing multiplies to 40 and adds to -6, it is impossible

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2 years ago
Rewrite this expression using the distributive property.<br> (3x2 + 4x-7)(x-2)
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D

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Each factor on the right has to be multiplied by the equation on the left and then you add them.

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