Answer:
x(t) = -1 + 4t
y (t) = 3 - 5t
Step-by-step explanation:
The end points of the line segment are (-1, 3) and (3, -2).
Let a = (-1,3) and b = (3,-2)
Now, find the value of (b-a)
(b-a) = ((3+1), (-2-3))
b-a = (4, -5)
Therefore, the parametrization of the given line segment is
r(t) = a + (b-a)t
r(t) = (-1,3) +(4,-5)t
r(t) = (-1+4t, 3-5t)
We can rewrite this as
x(t) = -1 + 4t
y (t) = 3 - 5t
Answer:
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)
Step-by-step explanation:
this might be right, sorry if im wrong
Answer:

Step-by-step explanation:
See attachment for complete question


From the question, we understand that one shrub must be at both ends.
Taking the first as a point of reference, we're left with:

Substitute 10 for n and d for distance



Hence:
answers the question
Answer:
y =1/2
Step-by-step explanation:
solve for ; y
10(1 – 2y) = -5(2Y - 1)
-10(2y-1) +5(2Y - 1) =0
(2y-1)(-10+5) = 0
-5(2y-1) =0
2y-1=0
y = 1/2