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IgorLugansk [536]
2 years ago
13

Aditi has $50. 00 in her wallet. She buys a shirt for $12. 00 and also wants to buy some bracelets that are on sale for $0. 60 e

ach. The inequality below relates x, the number of bracelets she can buy, with her shirt purchase and the money in her wallet. 12 0. 60 x less-than-or-equal-to 50 What is the greatest number of bracelets she could buy? 20 30 63 83.
Mathematics
1 answer:
aliya0001 [1]2 years ago
4 0

Answer:

12

Step-by-step explanation:

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(TIMED HELP) The population model describing the population of antelope in an area is:
Elena L [17]

Answer:

Step-by-step explanation:

The population model describing the population of antelopes in the area is

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

where n represents the number of years.

In the first year, the number of antelopes is given as 89, to find the number of antelopes for the second year, it means we are looking for P(1+1) = P2. We will substitute 1 for n and 89 for Pn+1

It becomes

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

P2 = [1.75×89^2 / (89 - 1)] + (32 -89)

P2 = [13861.75 / 88] - 57

P2 = 101

To find P3, we will substitute 101 for Pn+1 and 2 for n. It becomes

P3 = [1.75×101^2 / (101 - 1)] + (32 -101)

P3 = [17851.75 / 100] - 69

P3 = 110

To find P4, we will substitute 110 for Pn+1 and 3 for n. It becomes

P4 = [1.75×110^2 / (110 - 1)] + (32 -110)

P4 = [21175 / 109] - 78

P4 = 116

To find P5, we will substitute 116 for Pn+1 and 4 for n. It becomes

P5 = [1.75×116^2 / (116 - 1)] + (32 -116)

P5 = [23548 / 115] - 84

P5 = 121

To find P6, we will substitute 121 for Pn+1 and 5 for n. It becomes

P6 = [1.75×121^2 / (121 - 1)] + (32 -121)

P6 = [25621.75 / 120] - 89

P6 = 125

To find P7, we will substitute 125 for Pn+1 and 6 for n. It becomes

P7 = [1.75×125^2 / (125 - 1)] + (32 -125)

P7 = [27343.75 / 124] - 93

P7 = 128

To find P8, we will substitute 128 for Pn+1 and 7 for n. It becomes

P8 = [1.75×128^2 / (128 - 1)] + (32 -128)

P8 = [28672 / 127] - 96

P8 = 130

To find P9, we will substitute 130 for Pn+1 and 7 for n. It becomes

P9 = [1.75×130^2 / (130 - 1)] + (32 -130)

P9 = [29575 / 129] - 98

P9 = 131

To find P10, we will substitute 131 for Pn+1 and 7 for n. It becomes

P10= [1.75×131^2 / (131 - 1)] + (32 -131)

P10= [30031.75 / 130] - 99

P10 = 132

The correct option is C

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3 years ago
Mr and Mrs Kosley took their dog on a walk. Mr Kosley walks 5mph and Mrs Kosley walks 6mph. The dog walks 10mph. On the path, th
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Step-by-step explanation:

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3 years ago
Andy has 31 coins made up of quarters and half dollars, and their total value is $11.00. How many quarters does he have?
charle [14.2K]

Answer:

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Step-by-step explanation:

This situation has two unknowns - the total number of half dollars and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.

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We write the first equation in terms of q by subtracting it across the equal sign to get h=31-q. We now substitute this for h in the second equation.

0.50(31-q)+0.25q=11

15.5-0.50q+0.25q=11

15.5-0.25q=11

After simplifying, we subtract 15.5 across and divide by the coefficient of q.

-0.25q=-4.5

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We now know of the 31 coins that 4 are quarters.

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I need help with this problem
Vitek1552 [10]

Answer:

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