Given the points (2, 2) and (-1, -7) find the slope.

Mathematics

1 answer:

Softa [21]3 years ago

6 0

Slope is change in y over the change in x.

Slope = (-7 - 2) / (-1 -2)

Slope = -9/-3

Slope = 3

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Suppose we take a random sample of 41 state college students. Then we measure the length of their right foot in centimeters. We

Debora [2.8K]

Answer:

$ME = \frac{25.09-21.01}{2}= 1.69$

The general formula for the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

And for this case the width is:

$Width= 2*t_{\alpha/2} \frac{s}{\sqrt{n}}$

And if we decrease the confidence level from 95% to 90% then the critical value $t_{\alpha/2}$ would decrease and in effect the width for this new confidence interval decreases.

As confidence level decreases, the interval width decreases

Step-by-step explanation:

For this cae we know that the sample size selected is n =41

And we have a confidence interva for the true mean of foot length for students at a college selected.

The confidence interval is given by this formula:

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

And for this case the 95% confidence interval is given by: (21.71,25.09)

A point of etimate for the true mean is given by:

$\bar X = \frac{21.71+25.09}{2}= 23.4$

And the margin of error would be:

$ME = \frac{25.09-21.01}{2}= 1.69$

The general formula for the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

And for this case the width is:

$Width= 2*t_{\alpha/2} \frac{s}{\sqrt{n}}$

And if we decrease the confidence level from 95% to 90% then the critical value $t_{\alpha/2}$ would decrease and in effect the width for this new confidence interval decreases.

As confidence level decreases, the interval width decreases

3 0

3 years ago

A hot air balloon in flight begins to ascend at a steady rate of 120 feet per minute. After 1.5 minutes, the balloon is at an al

azamat

Answer:

The balloon will not reach 2,500 feet after 4 minutes.

Step-by-step explanation:

The equation of the line in the point-slope form is

$y-y_1=m(x-x_1)$