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Valentin [98]
3 years ago
10

Calculate the pOH of a solution that is 3.25x10^-10 M of Potassium hydroxide (KOH).

Chemistry
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

poH= 9.48

Explanation:

pOH= -log(concentration of a Strong Base)

since KOH is a strong base we simply

-log(3.25e-10)= 9.48

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Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. Suppose 94g of sulfuric acid is mixed with 49.9g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.

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First thing's first, we write out the balanced chemical equation;

2NaOH + H2SO4 --> Na2SO4 + 2H2O

The question hints that sulphuric acid would be in exess by asking to calculate the minium mass that would be left over.

We proceed by calculatng the amount of sulphuric acid that would react with  49.9g of sodium hydroxide.

From the reaction,

2 moles of NaOH reacts with 1 mole of H2SO4.

Calculate moles of sodium hydroxide:

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