Calculate the pOH of a solution that is 3.25x10^-10 M of Potassium hydroxide (KOH).
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535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
<h3>What is an ideal gas equation?</h3>The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given:
⇒
1 mole of is formed from 1 mole of charcoal, that means 1 mole of
is formed from 12 g of charcoal.
1 lbs = 453.592 grams
6.75 lbs = 6.75 x 453.592 =3061.746g
So, formed from 3061.746g of charcoal is:
= x 3061.746g
=255.14 mol.
Now, at STP, the volume of 1 mol of gas =22.4 L
Volume of 255.14 mol of = 255.14 x 22.4 L
Volume of 255.14 mol of = 535.8 L
Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
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