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Otrada [13]
3 years ago
15

Determine the mass of 2.4 x 10^24 atoms of gold?​

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

Mass = 785.9 g

Explanation:

Given data:

Atoms of gold = 2.4 × 10²⁴ atoms

Mass of gold = ?

Solution:

First of all we will convert the number of atoms into moles.

2.4 × 10²⁴ atoms × 1 mol/ 6.02 × 10²³ atoms

number of moles = 3.99 mol

Now we will determine the mass of gold.

Mass = number of moles × molar mass

Mass =  3.99 mol × 196.97 g/mol

Mass = 785.9 g

Anna007 [38]3 years ago
3 0

Answer:Mass = 785.9 g

Explanation:because i'll fegure it this out

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Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C
timofeeve [1]

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The Order is as follow,

                                     C-H < S-H < H-Br < H-Cl


Explanation:

                      Polarity depends on the electronegativity difference between two atoms, greater the electronegativity difference, greater will be the polarity of bond and vice versa.


Electronegativity Difference between Hydrogen and other given elements are as follow,


1) C-H;

               E.N of Carbon     = 2.55

               E.N of Hydrogen = 2.20

                                           ------------

               Difference              0.35


2) S-H;

               E.N of Sulfur       = 2.58

               E.N of Hydrogen = 2.20

                                           ------------

               Difference               0.38


3) H-Br;

               E.N of Bromine   = 2.96

               E.N of Hydrogen = 2.20

                                          -------------

               Difference              0.76


4) H-Cl;

               E.N of Chlorine   = 3.16

               E.N of Hydrogen = 2.20

                                           -----------

               Difference               0.96


Hence it is proved that the greatest electronegativity difference is found between H and Chlorine in H-Cl, therefore it is highly polar bond and vice versa.

7 0
3 years ago
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