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stealth61 [152]
3 years ago
12

The shadow of a flag pole is 28 ft long. the distance from the tip of the shadow to the top of the pole is 33 ft. how tall is th

e hole? round to tenths
Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$

Step-by-step explanation:

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The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

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When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

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When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

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Hence the correct match are -

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