Question:
A solar power company is trying to correlate the total possible hours of daylight (simply the time from sunrise to sunset) on a given day to the production from solar panels on a residential unit. They created a scatter plot for one such unit over the span of five months. The scatter plot is shown below. The equation line of best fit for this bivariate data set was: y = 2.26x + 20.01
How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?
Answer:
51.65 kilowatt hours
Step-by-step explanation:
We are given the equation line of best fit for this data as:
y = 2.26x + 20.01
On a day that has 14 hours of possible daylight, the model prediction will be calculated as follow:
Let x = 14 in the equation.
Therefore,
y = 2.26x + 20.01
y = 2.26(14) + 20.01
y = 31.64 + 20.01
y = 51.65
On a day that has 14 hours of daylight, the model would predict 51.65 kilowatt hours
I believe this would be 5x/2x-5
Hope this helps!
We know that
area of a circle=pi*r²
turn A
r=3 units------> 3*(1/10)----> 0.3 miles
area of a circle=3.142*0.3²-----> 0.28278 miles²
by proportion
0.28278/360°=A/90°------> A=90*0.28278/360------> A=0.0707 miles²
the answer is
0.0707 miles²
Answer:
You multiply the length and the width to get the area.
Step-by-step explanation: For example if the length was 5 and the width was four the answer would be 20 because 5x4=20
