J = K (1+ p/100) make p as a subject

Mathematics

1 answer:

olganol [36]2 years ago

8 0

Answer:

p = 100(J/K - 1)

Step-by-step explanation:

When we want to make a variable the subject of an equation, we want to get that variable by itself on one side of the equation - to unwrap it from all the operations attached to it.

Here's what the process looks like for p:

$J=K(1+p/100)\\J/K=1+p/100\\J/K-1=p/100\\p=100(J/K-1)$

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A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .