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2 years ago

J = K (1+ p/100) make p as a subject

Mathematics

1 answer:

olganol [36]2 years ago

8 0

Answer:

p = 100(J/K - 1)

Step-by-step explanation:

When we want to make a variable the subject of an equation, we want to get that variable by itself on one side of the equation - to unwrap it from all the operations attached to it.

Here's what the process looks like for p:

$J=K(1+p/100)\\J/K=1+p/100\\J/K-1=p/100\\p=100(J/K-1)$

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3 years ago

Evaluate the expression when x = 9. x + 5(x + 2)

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Answer:

Step-by-step explanation:

x + 5(x + 2)

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3 years ago

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Is 8 the HCF of 32, 48 and 72?

Sergio [31]

Step $1$

Find the factors of each number

we know that

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Step $2$

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3 years ago

5 ports Use absolute value to express the distance between -12 and -15 on the number line. |-12 - (-15) = -27

zloy xaker [14]

Answer:

$Distance = 3$

Step-by-step explanation:

Given

-12 and -15

Required

Solve the difference

The question you posted included the solution. However, the solution is incorrect;

The absolute difference is represented as:

$Difference = \vert a - b \vert$

In this case:

$a = -12$

$b = -15$

So, the distance is calculated as:

$Distance = |-12 - (-15)|$

Open bracket

$Distance = |-12 +15|$

$Distance = |3|$

$Distance = 3$

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3 years ago