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2 years ago

J = K (1+ p/100) make p as a subject

Mathematics

1 answer:

olganol [36]2 years ago

8 0

Answer:

p = 100(J/K - 1)

Step-by-step explanation:

When we want to make a variable the subject of an equation, we want to get that variable by itself on one side of the equation - to unwrap it from all the operations attached to it.

Here's what the process looks like for p:

$J=K(1+p/100)\\J/K=1+p/100\\J/K-1=p/100\\p=100(J/K-1)$

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2 years ago

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2 years ago

Read 2 more answers

What is the length of CD? In this diagram, <br> ABC ~ EDC.

Alex777 [14]

Hey there!

Answer:

CD = 3.

Step-by-step explanation:

Since the triangles are similar, we can set up a ratio to determine the other side-lengths:

$\frac{12-x}{18} =\frac{x}{6}$

Cross multiply:

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3 years ago

The graph of a quadratic function has a vertex located at (7,-3) and passes through points (5,5) and (9,5). Which equation best

Serga [27]

Answer:

B) $f(x)=2(x-7)^2-3$ .

Step-by-step explanation:

The vertex form of the equation is given by $f(x)=a(x-h)^2+k$ .

We plug in the vertex to obtain:

$f(x)=a(x-7)^2-3$ .

Since the graph passes through (5,5) and (9,5), they must satisfy its equation.

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Divide both sides by 4.

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Therefore the equation is:

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2 years ago