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juin [17]
2 years ago
11

J = K (1+ p/100) make p as a subject

Mathematics
1 answer:
olganol [36]2 years ago
8 0

Answer:

p = 100(J/K - 1)

Step-by-step explanation:

When we want to make a variable the subject of an equation, we want to get that variable by itself on one side of the equation - to unwrap it from all the operations attached to it.

Here's what the process looks like for p:

J=K(1+p/100)\\J/K=1+p/100\\J/K-1=p/100\\p=100(J/K-1)

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A survey was given to 339 people asking whether people like dogs and/or cats.
liubo4ka [24]

Answer:

80.

Step-by-step explanation:

Let C be the set of people who like cats and D the set of people who like dogs. Under the cardinality theorem you have

n(CUD) = n(C) + n(D) - n(CnD)[/tex], isolating the (C∩(D , you have n(C∩(D  = n(C) + n(D) - (C∪.As a total of 339 individuals, and 88 are those who do not like cats or dogs, then 251 of them are those who like cats or dogs. Then, n[tex](C∩(D  = 190 +141 -251 = 80

6 0
3 years ago
Find the quotient of 85 and 4find the quotient of 85 and4
nignag [31]

Quotient is 21

<u>Step-by-step explanation:</u>

Step 1:

Divide 85 by 4. Using long division method, find the quotient.   

  <u>21</u><u> </u>

4|85

  8

-------

     5

  -  4

--------

      1

4 0
3 years ago
Which rule can you use to find the nth term of an arithmetic sequence in which the common difference is 5 and a12 = 63?
iren2701 [21]
Tn = a + (n-1)d

when n  = 12, tn  = 63

63 = a + (12-1)*5

a = 63 - 55 =8

tn or an 
= 8 + (n-1) 5

=  3 + 5n

Hope this helps
4 0
3 years ago
At Garland School,
ankoles [38]

490 x 2/5 = 980/5 = 196 girls at Garland


945 x 5/7 = 4725/7 = 675 girls at Bowood


Bowood has more girls:

675-196 = 479 more

8 0
2 years ago
Rate of change of 15
konstantin123 [22]

Answer:A General Note: Rate of Change

The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

Step-by-step explanation:

4 0
3 years ago
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