Solution :
We have to prove that 
(De-Morgan's law)
Let 
then 
and 
and so 
and 
.
Thus, 
and so 
Hence, 
.........(1)
Now we will show that 
Let ⇒
Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.
and 
Therefore, 
and we have .............(2)
From (1) and (2),
Hence proved.
Answer:
x=3/4,y=5/2
Step-by-step explanation:
y=-x^2+4,y=2x+1
substitute y=-x^2+4 as y for y=2x+1
2x+1=-x^2+4, x=3/4(isolate "x")
x=3/4
substitute x=3/4 for 2x+1=-x^2+4
y=2*3/4+1
y=5/2
x=3/4, y=5/2
hope this helps!
Answer:
what do you need help with
Step-by-step explanation:
The number of hours that students have to work on homework will be 1/3 hours.
<h3>What is subtraction?</h3>
It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.
Mr. K's maths class is 1 and 1/4 hours long.
After working problems on the board for 55 minutes or 11 / 12 hour.
He gave the students the rest of the class period to work on homework.
Then the number of hours that students have to work on homework will be
⇒ 1 + 1/4 - 11/12
⇒ 5 / 4 - 11/ 12
⇒ (15 - 11) / 12
⇒ 4/12
⇒ 1/3 hours
More about the subtraction link is given below.
brainly.com/question/4319655
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