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Snowcat [4.5K]
3 years ago
14

Solve each system by eliminating one of the variables by addition or subtraction.

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

(=^w^=) hope this helps

Step-by-step explanation:

1. (10,2)

2. (2,0)

3. (6,2)

4. (0.5,7.5)

5. (3.3, 0.36)

6. (3.5, 2.5)

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Anna weighs 52 pounds. Patrick weighs x pounds. Write an expression for their combined weight.
Vladimir79 [104]
Anna+patrick
anna=52
patric=x
susitute
52+x
tada
combined weight=52+x
7 0
3 years ago
This is easy math!!! i just don’t know if this would be sas or sss
const2013 [10]

Answer:

Sas

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
-7w+8 (w+1)=w-7<br> Please show work
kvv77 [185]
Hello there.^••^

−7w+8(w+1)=w−7
w+8=w−7
w+8−w=w−7−w8=−7
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6 0
3 years ago
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Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by
viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0
3 years ago
Leo and Maggie volunteer at the local bird sanctuary.
sattari [20]

Answer:2.4

Step-by-step explanation:

12 * 20% = 12 * 0.20 = 2.4 hours

It will not last the entire shift.

7 0
2 years ago
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