This is a problem of Standard Normal distribution.

We have mean= 12 grams
Standard Deviation = 2.5 grams

First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:

$z= \frac{8.5-12}{2.5} =-1.4$

So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808

Thus, the probability that the strawberry weighs less than 8.5 grams is 0.0808

6 0

2 years ago

50 POINTS PLS HELP!!!

Viefleur [7K]

Answer:

1.) 90 ways

2.) 15,600 ways

3.) 24 ways

Step-by-step explanation:

1.) Let's say we are given 2 digits not equal to each other...The number of different orderings would be 2*1 = 2, or if we wanted the number of ways to order 2 digits chosen : 10*9 = 90 ways

2.) The number of ways to arrange 3 letters from 26 letters is:

26 Permutes 3 = 26! / (26 -3)! = 26*25*24 = 15,600 ways to choose 3 letters in a certain order

3.) 4 different chores. The number of ways to do them = 4*3*2 *1 = 24 ways

7 0

3 years ago

When converting between two measurement units, how can you tell which operation to use

german

Most of the time its juss common sense where you can point the right measurement with just sense i guess

7 0

3 years ago

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