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3 years ago

PLEASEE HELP IM BEGGING YOU

Mathematics

2 answers:

Mamont248 [21]3 years ago

8 0

Answer:

1 7/12

Step-by-step explanation:

Hope this helps!

Brainiest?

BaLLatris [955]3 years ago

4 0

Answer:

1 7/12

Step-by-step explanation:

Its 1 7

/12

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What's the answer and how do you get it

ycow [4]

That some the answer

7 0

2 years ago

In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer

stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = percentage of patients stop smoking when given sustained care.

So, Null Hypothesis, $H_0$ : p = 80% {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, $H_A$ : p $\neq$ 80% {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of patients who stop smoking when given sustained care = 80.2%

n = sample of patients = 192

So, the test statistics = $\frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }$

= 0.07

The value of z test statistics is 0.07.

Also, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.07) = 1 - P(Z $\leq$ 0.07)

= 1 - 0.52790 = 0.4721

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0

3 years ago

Which value is farther to the right on a number line 2.5^2 and √81

ankoles [38]

√81 is farther to the right becaue 2.5^2 = 6.25 and √81 is 9

8 0

2 years ago

The level of nitrogen oxides (nox) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies no

mina [271]

Answer: 0.533

Explanation: Note that

$x \ \textgreater \ I \\ \Leftrightarrow x - 0.3 \ \textgreater \ I - 0.3 \\ \\ \Leftrightarrow \boxed{\frac{x - 0.3}{0.1} \ \textgreater \ \frac{I - 0.3}{0.1}} (1)$

Let

$z_1$ = z-score for I.
$z_2$ = z-score for x.

The formula for z-score is given by

$\text{z-score} = \frac{(\text{data point}) - (\text{mean})}{(\text{standard deviation})}$

So,

$z_2 = \frac{x - 0.3}{0.1}$

$z_1 = \frac{I - 0.3}{0.1}$

Based on inequality in (1),

$z_2 > \ z_1$

So,

$P(x \ \textgreater \ I) = 0.01
\\
\\ \Leftrightarrow P \left (\frac{x - 0.3}{0.1} \ \textgreater \ \frac{I - 0.3}{0.1} \right ) = 0.01 
\\
\\ \Leftrightarrow P(z_2 \ \textgreater \ z_1) = 0.01
\\
\\ \Leftrightarrow 1 - P(z_2 \leq z_1) = 0.01
\\
\\ \Leftrightarrow \boxed{P(z_2 \leq z_1) = 0.99}$

Since $z_1$ and $z_2$ are z-scores and the level of nitrogen oxides are normally distributed, using normal distribution calculator (or table),

$z_1 = 2.326
\\
\\ \Leftrightarrow \frac{I - 0.3}{0.1} = 2.326
\\
\\ \Leftrightarrow I - 0.3 = 0.1(2.326)
\\
\\ \Leftrightarrow I - 0.03 = 0.2326
\\
\\ \Leftrightarrow \boxed{I \approx 0.533}$

4 0

3 years ago

3n^5 divided by 6n^3 simplified, thank

insens350 [35]

Answer:

$\frac{ {n}^{2} }{2}$

Step-by-step explanation:

$\frac{3 {n}^{5} }{6 {n}^{3} } = \frac{3}{6} \times \frac{ {n}^{5} }{ {n}^{3} } = \frac{1}{2} \times {n}^{5 - 3} = \frac{1}{2} \times {n}^{2} = \frac{ {n}^{2} }{2}$

3 0

2 years ago