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3 years ago

PLS HELPP I WILL MARK BRAINLIEST!!

Mathematics

2 answers:

Tpy6a [65]3 years ago

8 0

The answer is 2 first you add then multiple

anastassius [24]3 years ago

3 0

The answer is 2. Just add and multiply

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What is the domain and range

Rainbow [258]

Well, keep in mind that the domain of a function is the entire set of possible values of the independent variable. To make it more clear, the domain is the set of all possible x-values, which will make the function work, and with real y-values as the output. So, the range would be the set of all of the second elements of an ordered pair (y-coordinates).

If you made a T chart like the picture you have above, you would have to put x (age of person) and y (books read).

So,

x = age of person

y = books read

4 0

3 years ago

Solve the inequality 6x - 8 > 4x + 26.

Mashutka [201]

Answer:

the answer is x>17 I hope it helps you and next time use mathpapa

3 0

3 years ago

Find

shepuryov [24]

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

Let the odd numbers be represented with x and y

Let x be the greater number

$x + 5y = 92$

Required

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

$x = y + 2$

Substitute y + 2 for x in $x + 5y = 92$

$y + 2 + 5y = 92$

Collect Like Terms

$y + 5y = 92 - 2$

$6y = 90$

Divide both sides by 6

$\frac{6y}{6} = \frac{90}{6}$

$y = \frac{90}{6}$

$y = 15$

Substitute 15 for y in $x = y + 2$

$x = 15 + 2$

$x = 17$

Hence; the two odd numbers are 15 and 17

4 0

3 years ago

Katie has $120 on her cafeteria card. Every time she orders a meal, $4.50 is deducted from the value on her card. The amount of

OLga [1]

Answer:

i think it's 11 meals have been ordered

4 0

3 years ago

True or false: (a) If A2 is defined then A is necessarily square. (b) If AB and BA are defined then A and Bare square. (c) If AB

andrew-mc [135]

(a) True. Suppose A is a not a square matrix, with m rows and n columns. Then A² is not defined, because you can't multiply an m×n matrix by another m×n matrix.

(b) False. As an example, consider the matrices

$A_{3\times2} = \begin{bmatrix}1&0\\0&1\\0&0\end{bmatrix}$

$B_{2\times3} = \begin{bmatrix}-1&0&1\\0&0&1\end{bmatrix}$

Then both AB and BA are defined, with

$AB_{3\times3} = \begin{bmatrix}-1&0&1\\0&0&1\\0&0&0\end{bmatrix}$

$BA_{2\times2} = \begin{bmatrix}-1&0\\0&0\end{bmatrix}$

In general, you can multiply any m×n by any n×m matrix.

(c) True. Multiplying a m×n matrix by a n×m matrix always yields a m×m matrix, and multiplying a n×m matrix by a m×n matrix always yields a n×n matrix.

4 0

2 years ago