You can find the slope either by just looking at the line or using the slope formula.
#1: The slope formula is:
Find two points and plug it into the formula
I will use (0, 2) and (1, -1)
(0, 2) = (x₁, y₁)
(1, -1) = (x₂, y₂)
![m = \frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
[two negatives cancel each other out and become positive]
![m=\frac{2+1}{-1} =\frac{3}{-1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B2%2B1%7D%7B-1%7D%20%3D%5Cfrac%7B3%7D%7B-1%7D)
m = -3
#2: To find the slope without having to do the work, you use this:
![m=\frac{rise}{run}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7Brise%7D%7Brun%7D)
Rise is the number of units you go up(+) or down(-) from each point
Run is the number of units you go to the right from each point
If we start at a defined/obvious point, like (0, 2), find the next point and see how many units it goes up or down and to the right. The next point is (1, -1), so from each point, you go down 3 units and to the right 1 unit. So your slope is -3/1 or -3. You can make sure the slope is right by looking at another point.
((x2-x1),(y2-y1))
((6-5),(9-8))
Component form: (1,1)
(1^2+1^2)^(1/2)
Magnitude: (2)^(1/2)
Maybe:
Cos90=0
I’m not sure of the question here
What you see in the z score table is P(z< a constant), for P( z≥ a number), subtract the probability from 1:
1-0.1587=0.8413
on the z score table, you will see that p(z<1.00)=0.8413
so c=1.00