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Kamila [148]
2 years ago
11

Find the measure of the third angle of a triangle given the measures of two angles

Mathematics
1 answer:
sattari [20]2 years ago
7 0
We know that all three angles in a triangle must add to 180 degrees so we can use this fact to find the measure of the missing angles.  
180-57-101= 22 degrees
180-72-72=36 degrees
180-x-20=160-x degrees
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1. James wants to fill a tank with water. He already has 4 gallons in the 50 gallon tank. Using the equation y=2x+4, where y is
rusak2 [61]
Y=2(4)+4
=12 gallons in the tank so far

50-12
=38 gallons to fill
3 0
2 years ago
Suppose y varies directly with x. Write a direct variation equation that relates x and y when y = 6 and x = 12
Elenna [48]

Answer: 2

Step-by-step explanation: If 12/6=2 so the answer to the problem is 2 because 6x2=12

7 0
2 years ago
Read 2 more answers
Please help I need to get this done really bad
kupik [55]

Answer:

1 . 4 (x + 6)

2. 9 x × (x+9)

3. 3x× (x-6)

4. 225+75x

3 0
2 years ago
Choose the fraction that has not been reduced to simplest form 19/3810/1921/3415/18
lozanna [386]

19/38 and 15/18

Explanation:

19/38 can be reduced as there is a factor other than 1 that can divide without a remainder. Factor is 19

It can still be reduced because 19*2 = 38

19/38 = 1/2

10/19 cannot be reduced as there is no factor other than one to divide without a remainder

21/34 cannot be reduced as there is no factor other than one to divide without a remainder

15/18 can be reduced as there is a factor other than 1 that can divide without a remainder.

The factor is 3

15/18 = 5/6

Fraction that has not been reduced to simplest form are 19/38 and 15/18

5 0
10 months ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

106.26 = o

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

\frac{106.26}{360} (100)\pi

\frac{10626}{360} \pi

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

\frac{36}{2}  = 18

\sqrt{18(18 - 10)(18 - 10)(18 - 16)}

\sqrt{18(8)(8)(2)}

\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

Which is an approximate or

44.73

6 0
2 years ago
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