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Hitman42 [59]
3 years ago
6

Plsss help will give a good amount of points, need done asap

Mathematics
2 answers:
Alex3 years ago
7 0
4+2i because you can’t have a negative square root
maksim [4K]3 years ago
7 0

Answer:

4 + 2i

Step-by-step explanation:

Since

\sqrt{ - 1}  = i

4 +  \sqrt{ - 4}  = 4 +   \sqrt{ - 1 \times  {2}^{2} }  \\  = 4 +  2i

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Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
Scorpion4ik [409]

The horizontal asymptote of the function is the minimum number of deer in the area.

  • The equation of horizontal asymptote is: \mathbf{y = 40}
  • The horizontal asymptote means that, the number of deer will never be less than 40

The equation is given as:

\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

Expand the numerator

\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

Cancel out the common factor

\mathbf{f(x) = 40}

Hence, the equation of horizontal asymptote is:

\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

8 0
2 years ago
Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 16
s344n2d4d5 [400]

Answer:

k=3

Step-by-step explanation:

Let

f(x)=2x^3+18x^2-18x-162

We factor 2 to obtain;

f(x)=2(x^3+9x^2-9x-81)

We factor the polynomial within the parenthesis by grouping.

f(x)=2(x^2(x+9)-9(x+9)

f(x)=2(x^2-9)(x+9)

f(x)=2(x^2-3^2)(x+9)

We apply difference of two squares on the second factor: x^2-3^2=(x-3)(x+3)

f(x)=2(x+3)(x-3)(x+9)

We now compare to;

f(x)=2(x+k)(x-k)(x+9)

It is now obvious that k=3

6 0
3 years ago
How can i get the volume??
Paladinen [302]
Length times width times height gives you the volume of things
6 0
3 years ago
Please Help!!!
JulsSmile [24]

Answer:

The answer is d.

8 0
2 years ago
Read 2 more answers
Simplify (2^5/3^2)^4 I need help asap within 10 min
Daniel [21]

Answer:

\frac{2^{20} }{3^{8} }

Step-by-step explanation:

Exponent Multiplication Rule :

(\frac{x^{a} }{y^{b} } )^{c} = \frac{x^{ac} }{y^{bc} }

=============================================================

Solving :

⇒ (\frac{2^{5} }{3^{2} } )^{4}

⇒ \frac{2^{5(4)} }{3^{2(4)} }

⇒ \frac{2^{20} }{3^{8} }

3 0
2 years ago
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