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Angelina_Jolie [31]
3 years ago
6

Please help. Which data set is represented by the modified box plot?

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Sorry I'm late

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According to Jax's pedometer, he walked 2.783\,\text{km}2.783km2, point, 783, space, k, m while taking care of the livestock in
Airida [17]

We have been given that according to Jax's pedometer, he walked 2.783 km while taking care of the livestock in the morning and 3.124 km taking care of the livestock in the evening.

To find total walk of Jax while taking care of livestock we will add distances covered by Jax in the morning and evening.

\text{Total walk of Jax while taking care of livestock}=2.783+3.124

\text{Total walk of Jax while taking care of livestock}=5.907

Therefore, Jax walked 5 km and 907 m while taking care of the livestock.  

7 0
3 years ago
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What is the slope of line t?
Korolek [52]
------------------------------------------------------------------------------------------
Identify two coordinates on the graph
------------------------------------------------------------------------------------------
( 0, -1) and (3, 0)


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Apply the formula for Slope
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\boxed{ Slope = \frac{Y_2-Y_1}{X_2 - X1} }

\boxed {Slope = \frac{0-(-1)}{3-0}}

\boxed { Slope = \frac{1}{3} }


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Answer: Slope = 1/3
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7 0
3 years ago
1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+8+9+9+0+0
Rama09 [41]

90

6+6=12

12+8=20

20+10=30

30+12=42

42+14=56

56+16+18=90

4 0
3 years ago
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I NEED THE ANSWER RIGHT NOWWWW
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Answer:

All of them would be under $65

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3 years ago
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Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
Sergio039 [100]
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive

We are given
P(A)=0.75  [ probability that Nathan is allergic ]
P(T|A)=0.98  [probability of testing positive given Nathan is allergic to Penicillin]

We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)

From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735

Hope this helps!!
3 0
3 years ago
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