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3 years ago

14

gabriel has 6 2/3 of almond flour to make macaroons. he plans to make a recipe that uses 3/4 of a cup of almond flour. what is t

he greatest number recipes he can make?

1 answer:

harina [27]3 years ago

6 0

Answer:

8 cups max

Step-by-step explanation:

3/4 cup = 1 recipe

6 2/3(20/3) cup = <u>20/3 x 1 </u>

3/4

= <u>20</u> / <u>3</u>

3 4

= <u>20</u> x<u> 4</u>

3 3

= 80/9

= 8 cups max

the 9th cup will not be enough.

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3. At the beach, you would like to fill 5 buckets with seashells. You have

MA_775_DIABLO [31]

Answer: It will be D

Step-by-step explanation: 5 divided by 8 is 1.2

5 0

2 years ago

Read 2 more answers

I need to finish this usa test prep now plz help

Slav-nsk [51]

Answer:

R = 101

S = 131

Step-by-step explanation:

First, you will want to get your angle T. Since T is on the same line as the angle with 128 degree, you can easily find angel T. They are supplementary angels and form 180.

T=180-128

T=52

You also know that all angles in a triangle equal to 180

Use that to find angle S

180 = R+S+T

180 = 79 + S + 52

180 - 79 - 52 = S

49 = S, exterior S = 180-49 = 131

Exterior R = 180 - 79 = 101

Now add all your exteriors

8 0

3 years ago

Which point lies on a circle with a radius of 5 units and center at P(6,1)?

ryzh [129]

Answer:

Option B. $R(2,4)$

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

$(x-6)^{2}+(y-1)^{2}=5^{2}$

$(x-6)^{2}+(y-1)^{2}=25$

step 2

Verify each case

case A) $Q(1, 11)$

substitute the value of $x=1, y=11$ in the equation of the circle and then compare the results

$(1-6)^{2}+(11-1)^{2}=25$

$25+100=25$ ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) $R(2,4)$

substitute the value of $x=2, y=4$ in the equation of the circle and then compare the results

$(2-6)^{2}+(4-1)^{2}=25$

$16+9=25$ ------> is true

therefore

the ordered pair R lie on the circle

case C) $S(4,-4)$

substitute the value of $x=4, y=-4$ in the equation of the circle and then compare the results

$(4-6)^{2}+(-4-1)^{2}=25$

$4+25=25$ ------> is not true

therefore

the ordered pair S not lie on the circle

case D) $T(9,-2)$

substitute the value of $x=4, y=-4$ in the equation of the circle and then compare the results

$(9-6)^{2}+(-2-1)^{2}=25$

$9+9=25$ ------> is not true

therefore

the ordered pair T not lie on the circle

7 0

3 years ago

Pls help me........ I tried lol

diamong [38]

its step 2 he did not subtract it right hope this helps and have a great day and get some sleep lol

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2 years ago

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If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num

Hitman42 [59]

Answer:

The original fraction is $\frac{6}{14}$ .

Step-by-step explanation:

Solution,

Let the fraction be' $\frac{x}{y}$ '.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

$\frac{x+2}{y+2}=\frac{1}{2}$

On using cross multiplication method, we get;

$2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1$

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

$\frac{x-2}{y-2}=\frac{1}{3}$

On using cross multiplication method, we get;

$3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2$

Now Substituting the equation 1 in equation 1 we get;

$3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6$

Now Substituting the value of x in equation 1 we get;

$y=2x+2\\\\y=2\times6+2 = 14$

Hence The original fraction is $\frac{6}{14}$ .

4 0

3 years ago