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2 years ago

HELP PLEASE

Mathematics

1 answer:

Georgia [21]2 years ago

7 0

Answer:

$\huge\boxed{\sf No}$

Step-by-step explanation:

Evan spent 20 hours doing homework last week

25 hours were spent this week.

<u>Let's see what 125% of 20 equals:</u>

= (125 / 100) * 20

= (125 / 10) * 2

= 125 / 5

= 25 hours

But,

<u>It is written that Evan thought he spent 125 % more than the last week which means:</u>

= (125% of 20) + 20

= 25 + 20

= 45 hours

He should've said that he has given 25% more time than the last week.

(<u>Note that:</u> 25 % of 20 equals 5 so 25 % more than last week will be equal to (25 % + 20) = (5+20) = 25)

$\rule[225]{225}{2}$

Hope this helped!

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Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions

forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23 = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

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If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

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2 years ago

Line A is perpendicular to line B. The slope of line A is -1/9 what is the slope of line b?

Pani-rosa [81]

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{-\cfrac{1}{9}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{9}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{9}{1}}\implies 9}$

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marusya05 [52]

Answer:

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Step-by-step explanation:

Divide both sides by 2 which will give you y=0.5x+3.

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Paha777 [63]

Answer:

D. 20.

Step-by-step explanation:

-17 - -37 = 20.

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Kyle.

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2 years ago

On a test that has a normal distribution, a score of 19 falls one standard deviation below the mean, and a score of 40 falls two

nexus9112 [7]

Hi there!

We can use the following equation:

$\large\boxed{z = \frac{x-\mu}{\sigma}}$

z = amount of standard deviations away a value is from the mean (z-score)

σ = standard deviation

x = value

μ = mean

Plug in the knowns for both and rearrange to solve for the mean:

$-1 = \frac{19-\mu}{\sigma}\\\\-\sigma = 19 - \mu\\\\ \sigma = -19 + \mu$

Other given:

$2 = \frac{40-\mu}{\sigma}\\\\2\sigma = 40- \mu\\\\ \sigma = 20 - \frac{\mu}{2}$

Set both equal to each other and solve:

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