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gregori [183]
3 years ago
5

Last year mr.peterson had a fence all the way around his garden. he can reuse all of the fence he had around the garden last yea

r, but he needs to buy more fencing to go around this year's garden. how many more meters of fencing is needed for this year's garden than last year
Mathematics
1 answer:
lakkis [162]3 years ago
4 0
First, you need to find out the perimeter of the fence and how much of the fence he had around his garden last year (leftovers) and subtract them I think.
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Is the data set "the colors of the leaves on a branch" quantitative or qualitative? If it is quantitative, is it discrete or con
Mice21 [21]

Answer:

Option C. qualitative

Step-by-step explanation:

A qualitative variable is the type of variable that can't be numerically expressed but can be categorized. The colors of the leaves on a branch can be categorized as green, yellow and orange etc. Thus, the colors of the leaves is a qualitative variable. So, the correct option is C.

6 0
3 years ago
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I need help with this​
azamat

Answer:

Let the amount of Danny be y

Therefore, lance will have 1/3y

Total fraction of cup is 1/1

y+y/3=1

4y/3=1

4y=3

y=3/4

therefore, lance had 3/4 of the cup of water

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3 years ago
The circumference of a circle is 119.32 kilometers. What is the circle's radius?
DochEvi [55]

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58.66 is the radius of the circle

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2 years ago
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olchik [2.2K]

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Step-by-step explanation:

6 0
2 years ago
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The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k
HACTEHA [7]

Answer:

The given function f(x)=\frac{2x}{3}-4 was replaced with f(x+k)=\frac{2x}{3}-6 then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is f(x)=\frac{2x}{3}-4\hfill (1)

and when x=x+k then f(x+k)=\frac{2x}{3}-6\hfill (2)

Now to find the value of k:

Put x=x+k in the function f(x)

f(x)=\frac{2x}{3}-4

f(x+k)=\frac{2(x+k)}{3}-4

f(x+k)=\frac{2x+2k}{3}-4\hfill (3)

Now comparing equations (2) and (3) we get

f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6

\frac{2x+2k}{3}-4=\frac{2x}{3}-6

\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0

\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0

\frac{2k}{3}+2=0

\frac{2k}{3}=-2

k=\frac{-2\times 3}{2}

k=-3

Therefore k=-3

Therefore the given function f(x)=\frac{2x}{3}-4 was replaced with  f(x+k)=\frac{2x}{3}-6 then the value of k is -3

that is k=-3.

7 0
2 years ago
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