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timofeeve [1]
3 years ago
15

A summer camp basketball coach is hired to work 10 hours per week. During a really busy first week, they were required to work 1

5 hours. What percentage of time did they work during the busy week? Show your work.
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

150%

Step-by-step explanation:

15 / 10 =

1.5 =

150%

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Assistance if you please?
dybincka [34]

Answer:

38°

Step-by-step explanation:

a whole circle is equal to 360 degrees so if 52 +90= 142 the opposite side also equals 142 because they are clearly the same size. ED and AB are also the same sizes. if 360- (142+142) = 284. then you will have to divide 284 by 2. so 284÷2=76 and 76÷2=38°

hope you understand, I not that good at explaining things

also I don't know what the m means in mED

7 0
3 years ago
Estimate the product. Solve using an area model and the standard algorithm. Remember to express your products in standard form.
snow_tiger [21]

Answer:

Step-by-step explanation:

Using the area model and standard algorithm, we have:

                332   (tenths)

         <u> ×       21  </u>

                332

        <u>      664     </u>

        <u>      6972  </u> tenths = 697.2

<u />

              30      +      3      tenths

     1       300           32         332

    20     600           64         664

33.2 × 21 =<u>    30    </u> × <u>    1     </u>  =  <u>      30     </u>

8 0
3 years ago
−2⋅f(−6)−7⋅g(−7)=<br> what is the answerrr
Mrrafil [7]

Answer:

idk know dude I'm sorry

4 0
3 years ago
What is the value of 1/2 ÷ 1/3? Use pattern blocks to represent and find this value. The yellow hexagon represents 1 whole. Expl
ziro4ka [17]
1/2 x 3 = 3/2 or 1.5 or 1 1/2
4 0
3 years ago
A time for the 100 meter sprint of 14.9 seconds at a school where the mean time for the 100 meter sprint is 17.6 seconds and the
kirza4 [7]

Answer:

Z-score = -1.285

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.6 seconds

Standard Deviation, σ = 2.1 seconds

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

For x = 14.9, we have:

z_{score} = \displaystyle\frac{14.9-17.6}{2.1} = -1.285

A z-score to be unusual if its z-score is less than -2.00 or greater than 2.00.

Thus, the z-score is not unusual as it lies in the range [-2.00, 2.00]

6 0
3 years ago
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