The anwser is C there you go
36 cm^2
Step-by-step explanation:
<u>Small</u><u> </u><u>window</u>
Length: 2cm
Width: 2cm
<u>Area</u><u>:</u> 4 cm^2
<u>Big window</u>
Length: 4cm
Width: 3cm
<u>Area</u><u>:</u> 12 cm^2
Total area of the windows:
(Area of 4 small windows + area of 1 big window)
(4 cm^2 x 4 + 12cm^2)
= <u>28 cm^2</u>
<u>Above</u><u> </u><u>window</u><u> </u><u>(</u><u>approx</u><u>.</u><u>)</u>
<u>Rectangle</u>
Length: 3cm
Width: 2cm
<u>Area</u><u>:</u> 6 cm^2
<u>T</u><u>riangle</u>
Base: 1cm
Height: 1cm
<u>Area</u><u>:</u> 2 x 0.5 cm^2 = 1 cm^2
<u>Square</u><u> </u><u>(</u><u>between</u><u> </u><u>the</u><u> </u><u>triangles</u><u>)</u>
Length: 1cm
Width: 1cm
<u>Area</u><u>:</u> 1 cm^2
= 8 cm^2
<u>TOTAL</u><u> </u><u>AREA</u><u> </u><u>OF</u><u> </u><u>ALL</u><u> </u><u>WINDOWS</u>
= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW
= 16 cm^2 + 12 cm^2 + 8 cm^2
<h3>
= <u>
36 cm^2</u></h3>
<em>I</em><em> </em><em>hope</em><em> </em><em>I</em><em> </em><em>made</em><em> </em><em>the</em><em> </em><em>explanations</em><em> </em><em>clear</em><em> </em><em>enough</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>it</em><em> </em><em>easier</em><em> </em><em>for</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>understand</em><em>!</em>
We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
Answer:
AAA (Or even just two angles work too, since the last has to be the same no matter what) ASA and SSS
Step-by-step explanation:
I believe this is the same as before? As far as I know these are the main rules for proving similarity. (AAS and A** do not exist (Brainly won't let me say the two Ss), make sure no trick questions get you ;p)
I'm not sure if what you needed earlier was the relationships between angles to find them? Like to find Exterior Angles subtract <C from 180 = <EA?
The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by
The sum is
approximately 2.66.
