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polet [3.4K]
3 years ago
6

What is the volume of the following rectangular prism pls help me I’m being timed

Mathematics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

ummmmm I guess I could add the dimensions in the text.

Step-by-step explanation:

The picture is a black screen.

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In how many ways can 7 people line if A needs to be first or last and B needs to be in the middle
12345 [234]

Answer:

<em>Assuming person A and person B are part of the 7 people</em>, there are 10 ways the 7 people can line up if A needs to be first or last and B needs to be in the middle.

Step-by-step explanation:

There are 2 places for A (first, last) and 5 places for B (anywhere but first or last). 2 x 5 = 10.

8 0
3 years ago
PLEASE ANSWER I WILL GIVE YOU BRAINIEST!!!!!!!!!!!!!!!!!!!!!!
Radda [10]

Answer:

C. x > 15

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose 80% of people enjoy swimming. Suppose 70% of people enjoy running.
Ede4ka [16]

Answer:

95%

Step-by-step explanation:

In this case we can apply a formula that tells us that:  

# (AUB) = #A + #B - #AnB  

Where A would be the ones who enjoy swimming and B would be the ones who enjoy running. AnB is the intersection of both sets, that is, those who enjoy doing both things, these values we have, if we replace them we have left:

#(AUB) = 80% + 70% - 55%

#(AUB) = 95%

Which means that 95% of people enjoy either swimming or running

6 0
3 years ago
Please show your work!!!!
viva [34]

Answer:

4√34

Step-by-step explanation:

Let the unknown side be y

y^2 = 20^2 + 12^2

y^2 = 400 + 144

y^2 = 544

Take the square root of both side

y = √544

y = √(16x34)

y = √16 x √34

y = 4√34

6 0
3 years ago
You decide to play roulette 4 times, each time betting on red. What is the distribution of X, the number of times you win?
aalyn [17]
  <span> 1.
If betting on red, 18/38 = 9/19 chance of winning, so 10/19 chance of losing
Chance of winning 4 times: (9/19)^4 = 6561/130321 =~ 5.034%
Chance of winning 3 times: (9/19)^3 * (10/19) * C(4,1) = 29160/130321 =~ 22.3755%
Chance of winning 2 times: (9/19)^2 * (10/19)^2 * C(4,2) = 48600/130321 =~ 37.2925%
Chance of winning 1 time: (9/19) * (10/19)^3 * C(4,3) = 36000/130321 =~ 27.624%
Chance of winning 0 times: (10/39)^4 = 10000/130321 =~ 76.7336% </span>
3 0
3 years ago
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