Given:
The expression is:
To find:
The difference.
Solution:
We have,
It can be rewritten as:
Taking LCM, we get
Therefore, the value of the difference is 
.
<u>ANSWER:
</u>
Zach has 28 dimes and 7 quarters.
<u>SOLUTION:
</u>
Given, Zach has 4 times as many dimes as quarters
And they have a combined value of 455 cents,
We need to find how many of each coins does he have?
Let, the number of dimes be x and number of quarters be y.
Then, x = 4y → (1)
Total combined value = 455 cents
x(value of one dime) + y(value of one quarter) = 455 cents
x(10 cents) + x(25 cents) = 455 cents
10x + 25y = 455 → (2)
Now, substitute (1) in (2)
10(4y) + 25y = 455
40x + 25y = 455
65y = 455
y = 7
substitute y value in (1)
x = 4(7) = 28
Hence, zach has 28 dimes and 7 quarters.
Answer:
Step-by-step explanation:
The position equation is given as
and we are looking for the times when the position of the ball is 9 feet. That means that we simply plug in a 9 for s(t) and factor to solve for t:
and
and this is what we factor to find t:
t = .42 sec and then again on its way back down at t = .89 sec
Answer:
-3
Step-by-step explanation:
-3x - 4 < 5
-3x < 9
x < -3
