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3 years ago

8

I need to find the slope

1 answer:

dangina [55]3 years ago

6 0

Answer:

1/-4

Step-by-step explanation:

(2,-3),(-2,-2)

-2 + 3/ -2 - 2

1/-4

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One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago

Please answer what the answer for ? Is.

vitfil [10]

Answer:

5/8

Step-by-step explanation:

A. 2/3 × 4/5 × m = 1/3 B. 4/5 × 2/3 × m = 1/3

8/15 × m = 1/3 8/ 15 × m = 1/3

m = 1/3 ÷ 8/15 m = 1/3 ÷ 8/15

m = 1/3 ×15/8 m = 1/3 × 15/8

m = 5/8 m = 5/8

C. 2/3 × 4/5 = 1/3 ÷ m

8/15 = 1/3 × 1/m

8/15 = 1/3m cross multiply

(3m) × (8) = 15

24m = 15

m = 15/24

m= 5/8

4 0

3 years ago

3x/2 - x = x/10 - 6/5

SVETLANKA909090 [29]

Answer: -3

X = -3

Step-by-step explanation:

Multiply the numbers i hope this helps god bless

8 0

2 years ago

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Nataly_w [17]

The answer to the question is C.

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2 years ago

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Ben walks at a rate of 3 miles per hour. he runs at the rate of 6 miles per hour. in one week, the combined distance that he wal

9966 [12]

If he only runs he ran 35 hours that and if he only walked he walked 70 hours that week

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3 years ago

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