That would be only rotational motion
Answer:
B=μ₀I/2r
Explanation:
Produced magnetic field due to an existing electric field through a coil or conductor can be explained by Biot-Savart Law. Formula for this law is:
dB=(μ₀I/4π.r²)dL
Here,
r=Radius of the loop
I and r are constants with respect to length L.
To convert linear displacement L into angular displacement Ф:
dL=r.dФ
So,
dB=(μ₀I/4π.r²)r.dФ
dB=(μ₀I/4π.r)dФ
Integrating both sides over the circle i.e. from 0 radians to 2π radians (360⁰), while the integration will apply only on dФ as all others are constants.
B=(μ₀I/4πr)(2π-0)
<u>B=(μ₀I/2r)</u>
Explanation:
Given that,
Length of the spring, l = 50 cm
Mass, m = 330 g = 0.33 kg
(A) The mass is released and falls, stretching the spring by 28 cm before coming to rest at its lowest point. On applying second law of Newton at 14 cm below the lowest point we get :
(B) The amplitude of the oscillation is half of the total distance covered. So, amplitude is 14 cm.
(C) The frequency of the oscillation is given by :
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.
When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
The Normal Force = M x G x Cos(theta)
= 9.5 Kg x 9.8 m/s^2 x cos 23
= 9.5 Kg x 9.8 m/s^2 x 0.9205
Converting Kg to Newton,
1 Kg = 9.81 N
= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205
= 840.702 N
