Answer:
Option B) This minimizes the harmful side effects of the radiations
Explanation:
Half-life is the time taken for the decay of an radio-active atom in which it disintegrates such that it becomes half of its value at the beginning.... The nuclei should be in active mode for a longer duration sufficient for the treatment of the condition but these nuclei should have a sufficient shorter half life so that they don't get enough time to cause any damage to the health of the person other than treating the cause.
A shorter half life gives the assurance that the radiation after the treatment will leave the body without getting accumulated and cause harm to the body cells and other organs.
Answer:
energy is stored is 2.2 × 10⁻¹³ J
Explanation:
The capacitance of the cell is given with the expression
C = (KE₀A) / d
k is the dielectric constant, A is the area of the cell, d is the thickness of the cell.
Now given that; the diameter is 50,
Area A = 4πR²
A = 4π × ( 25 × 10⁻⁶ m)²
A = 7850×10⁻¹² m²
our capacitance C = (KE₀A) / d
C = [9 ( 8.85 × 10⁻¹² C²/N.m² × 7850×10⁻¹² m² )] / 7×10⁻⁹ m
C = 8.93 × 10⁻¹¹ F
Now Energy stored
E = 1/2 × CV²
E = 1/2 × (8.93 × 10⁻¹¹ F) × ( 70 × 10⁻³ V)²
E = 2.2 × 10⁻¹³ J
Therefore energy is stored is 2.2 × 10⁻¹³ J
The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .
<h3>What is velocity with example?</h3>
The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.
<h3>Briefing:</h3>
Given the initial velocity of the ball (u) = 0
Distance travelled by the ball (s) = 200m
Acceleration (a) = 10 m/s²
As we know:
v² = u² + 2as
Putting values:
v² = 0+2 × (10 m/s²) × (200 m)
v = 44.73 m/s.
To know more about Velocity visit:
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Frequency=f
T=period of motion
f=1/T therefore f=1/2=0.500Hz or 0.5Hz
Hope this helps. Any questions please just ask. Thank you.
Answer: 
Explanation:
Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:
This means the absolute zero point of the Kelvin scale is 
Keeping this in mind, we have the freezing point and boling point of Methane as:
Freezing point: 
Boiling point: 
According to this, there is a linear relation between the methane scale (
) and the Kelvin scale in the form:
(1)
Where:
is the temperature in Kelvin
is the temperature in degrees Methane
Firstly, we need to find the value of 
and 
with the two given points (
and 
):
When 
and 
:
(2)
When 
and 
:
(3)
Now we have the linear equation:
(4)
Isolating :
(5)
Evaluating for 
:
(6)
Finally:
This means 
