Answer:
Option A. Rectangle
Step-by-step explanation:
we know that
If a cross section of the paperweight is cut parallel to the base, then the shape of the cross section will be equal to the base
The base is a rectangle with dimensions length 10 cm, width 4 cm
therefore
The cross section is a rectangle with dimensions length 10 cm, width 4 cm
The first step to solving this expression is to factor out the perfect cube
![\sqrt[3]{m^{2} n^{3} X n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B2%7D%20%20n%5E%7B3%7D%20X%20n%5E%7B2%7D%20%20%20%7D%20)
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
Finally,, reduce the index of the radical and exponent with 3
n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
This means that the correct answer to your question is n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%7D%20)
.
Let me know if you have any further questions
:)
11w(w-22) Multiply 11w times each term in the parenthesis
7=x^2+20x+82
0=x^2+20x+75
What adds to 20 and multiplies to 75? 5 and 15.
x^2+5x+15x+75
x(x+5) 15(x+5)
(x+15) (x+5)
Zeroes are x= -5 and x= -15
Answer:
addition property
Step-by-step explanation: