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Nuetrik [128]
3 years ago
8

Solve: (Y - 1.2895)/ 18594 = 18590 (Y-1.8590)

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0

I dont know how to do this, but download this app called "Photo math" and it will show u the answer and the work to solve this problem.


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If a triangle has a base of 5 cm and a height of 6 cm what’s it’s area?
Margarita [4]

Answer:

the area is 30 you have to muiltly the two together

Step-by-step explanation:

4 0
3 years ago
Simplify: -14cd-2c^2d^2+15cd+9c^2d^2-15cd
MaRussiya [10]

7c^2d^2-14cd

Hope this helps a bunch!!!!!!!!!!!!

7 0
3 years ago
Someone help please.
malfutka [58]

Answer:

$27

Step-by-step explanation:

If the table was marked up 125%, you can find the retail price of it this way:

20 + 1.25(20) = retail price

$45 = retail price.

To find 40% off of that, use

$45 - .4($45) = sale price

$27 = sale price (aka discount price)

5 0
3 years ago
Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

7 0
2 years ago
2 1/2x−34(2x+5)=3/8 what id X ?
Phantasy [73]
2 because I looked it up on google
3 0
2 years ago
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