Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Answer:
x = 28.744
Step-by-step explanation:
Seeing as this is a right triangle, and you're given an angle, an unknown measurement to the opposite side, and the measure of the adjacent side. You can use trig functions. In this case, tangent, because you are given the opposite and adjacent, and tangent covers opposite/adjacent.
Tan(32)=x/46
Tan(32)46=x
28.744=x
Answer:
151434/358 = 423
Step-by-step explanation:
Every product with non-zero factors can be written as an equivalent division relation.
a·b = c ⇒ a = c/b
Here, we have 35.8 × 4.23 = 151.434. This can be written as the equivalent ...
4.23 = 151.434/35.8
We can multiply this by 100 to get a division relation with a quotient of 423:
423 = 15143.4/35.8
If we want, we can move the decimal points another place to the right to get ...
151434/358 = 423
Triangles a are similar because they have the same degrees
And Triangles d are similar because they are the same shape
Step (1) Flip the equation
−10x+6=y
Step (2) Add -6 to both sides
−10x+6+−6=y+−6
−10x=y−6
Step (3) Divide both sides by -10
−10x−10=y−6−10
ANSWER
