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3 years ago

9

Sheila has a bag of 40 marbles. 10 of them are blue, 12 of them are green and the rest of them are red. What is the probability

that Sheila will get a red marble if she pulls it at random from the bag.

1 answer:

Schach [20]3 years ago

8 0

Answer:

18

Step-by-step explanation:

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You are given the system of equations to solve by the elimination method, which is an INCORRECT step that will NOT produce a sys

Karo-lina-s [1.5K]

C would be the correct answer. You caanot multiply just one part of an equation, you must multiply the whole thing. All of the other steps follow this rule, so C is an incorrect step, and is therefore the correct choice.

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5 0

3 years ago

Read 2 more answers

The sum of a number and its ____________ is zero.

arsen [322]

Negative counterpart

5 + -5 = 0

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3 years ago

4x+1=2x+11 what is the value of x

egoroff_w [7]

X = 5!

4x+1=2x+11
-1 -1 (Subtract 1 from both sides)
4x =2x+10
-2x -2x (Subtract 2x from both sides)
2x = 10
—— ——
2x 2x (Divide both sides by 2x)

X = 5

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3 years ago

For what values of x does the curve y^2x^3-15x^2=4 have horizontal tangent lines

enyata [817]

We have the following curve:<span>

$y^2x^3-15x^2=4$

To find the tangent lines to the curve we need to use the concept of derivative, but we can’t solve this problem for $y$ , thus, let's apply implicit differentiation, so:

$\frac{d}{dx}(y^2x^3-15x^2=4) \\ \\
\frac{d}{dx}(y^2x^3)-\frac{d}{dx}(15x^2)=\frac{d}{dx}(4) \\ \\
(y^{2})'x^3+(x^3)'y^2-15(x^2)'=0 \\ \\ 2yy'x^3+3x^2y^2-30x=0 \\ \\
y'=\frac{dy}{dx}=\frac{30x-3x^2y^2}{2x^3y}=\frac{x(30-3xy^2)}{2x^3y} \\ \\
y'=\frac{30-3xy^2}{2x^2y}$

Therefore the horizontal lines occurs when $y'=0$ , then:

$\frac{30-3xy^2}{2x^2y}=0 \\ \\ That \ is, \
when: \\ \\ 30-3xy^2=0 \\ \\ \therefore xy^2=10 \rightarrow y^2=\frac{10}{x}$

If we substitute this in the original equation we have:

$\frac{10}{x}x^3-15x^2=4 \\ \\ \therefore
10x^2-15x^2=4 \\ \\ \therefore x^2=-\frac{4}{5}$

This is an absurd result because it is impossible for a squared number to get a negative number. So the conclusion is that there is no any value of $x$ in which the curve has horizontal tangent lines.</span>

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Yuri [45]

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