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Yanka [14]
2 years ago
12

function a and function b are linear functions. function a is represented by the table values. function b is represented by the

equation y=3x+4
Mathematics
1 answer:
Kryger [21]2 years ago
7 0

The y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B

<h3>Linear functions </h3>

The standard linear equation is expressed as y = mx + b

For the given table;

The y-intercept occur at x = 0

y = 3x + 4

y = 3(0) + 4

y = 4

For the table;

Using the coordinate points (1, 2) and (3,10)

rate of change "m" = 10-2/3-1
m = 8/2

m = 4

Recall that y = mx + b

2 = 4(1) + b

b = -2

Hence the y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B.

Learn more on intercept here: brainly.com/question/25722412

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It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
2 years ago
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

  c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation

  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

  s = 65000 -2c . . . . . . . expression we can substitute for s

  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

_____

Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

6 0
3 years ago
Kirsten has to walk 2 3/4km to school. How far has she walked when she halfway? Give your answer in metres.
evablogger [386]

Answer:

375 m

Step-by-step explanation:

\frac{3}{4}  \times 1000 = 750

From halfway

\frac{750}{2}  = 375

Follow me and text me if you need anything in math.

6 0
2 years ago
Please help!! thank you
shutvik [7]

Answer: 5

Step-by-step explanation:

f(x)=3-x

f(-2)=3-(-2)

f(-2)=3+2

f(-2)=5

Hope this helps!! :)

Please let me know if you have any question

8 0
2 years ago
Interpret the average rate of change of -14/3 that
Jobisdone [24]

Answer:

On average, the slide drops 14 feet for every 3 feet of horizontal distance.

On average, the slide drops about 4.7 feet for every 1 foot of horizontal distance.

5 0
3 years ago
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