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Yanka [14]
2 years ago
12

function a and function b are linear functions. function a is represented by the table values. function b is represented by the

equation y=3x+4
Mathematics
1 answer:
Kryger [21]2 years ago
7 0

The y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B

<h3>Linear functions </h3>

The standard linear equation is expressed as y = mx + b

For the given table;

The y-intercept occur at x = 0

y = 3x + 4

y = 3(0) + 4

y = 4

For the table;

Using the coordinate points (1, 2) and (3,10)

rate of change "m" = 10-2/3-1
m = 8/2

m = 4

Recall that y = mx + b

2 = 4(1) + b

b = -2

Hence the y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B.

Learn more on intercept here: brainly.com/question/25722412

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G(x)=−4x+4, find g(3)
Igoryamba

»»————- ★ ————-««

I believe your answer is:  

g(3) = -8

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Evaluating the function...}}\\\\g(x)=-4x+4; g(3)\\\\--------------\\\rightarrow g(3)=-4(3)+4\\\\\rightarrow g(3) = -12  + 4\\\\\rightarrow \boxed{g(3)=-8}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
The cube root is the same as______
Ksju [112]

Answer:

the third root

Step-by-step explanation:

4 0
2 years ago
Need Help!!!! Please!!! Explain!!!! Don't Understand!!!
Arturiano [62]

90  it is a right tranigle

6 0
3 years ago
What is the maximum number of possible extreme values for the function f(x)=x^4+x^3-7x^2-x+6
notka56 [123]

A 4th degree polynomial will have at most 3 extreme values. Since the degree is even, there will be one global extreme, with possible multiplicity. The remainder, if any, will be local extremes that may be coincident with each other and/or the global extreme.


(The number of extremes corresponds to the degree of the derivative, which is 1 less than the degree of the polynomial.)

3 0
3 years ago
Read 2 more answers
suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in
Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = \frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}credit hours * gpa

in our case, it would be:

CGPA = \frac{(2.75*105)+(4*15}{105+15}

=> \frac{(288.75)+(60)}{120}

=> \frac{348.75}{120}

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0
4 years ago
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