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Yanka [14]
2 years ago
12

function a and function b are linear functions. function a is represented by the table values. function b is represented by the

equation y=3x+4
Mathematics
1 answer:
Kryger [21]2 years ago
7 0

The y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B

<h3>Linear functions </h3>

The standard linear equation is expressed as y = mx + b

For the given table;

The y-intercept occur at x = 0

y = 3x + 4

y = 3(0) + 4

y = 4

For the table;

Using the coordinate points (1, 2) and (3,10)

rate of change "m" = 10-2/3-1
m = 8/2

m = 4

Recall that y = mx + b

2 = 4(1) + b

b = -2

Hence the y-intercept of B is greater than the y-intercept of A and the rate of change of function A is less than the rate of change of B.

Learn more on intercept here: brainly.com/question/25722412

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trasher [3.6K]

Answer:

S^2 = r^2 + t^2

Step-by-step explanation:

Also you can write it as:

S=sqrt( r^2 +t^2)

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In the monthly payment formula , what value would you put for r if the interest rate is 5.7%?
natulia [17]
In the monthly payment formula r is the percentage rate as a decimal.

To turn a percentage into a decimal, move the decimal point 2 places to the left.
 5.7% becomes 0.057

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0.8 rounded to nearest hundred
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A. 0
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6 0
2 years ago
Nick bought a new car.
ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

A(t) = A(0)(0.88)^t.

It halves in value at t years, for which A(t) = 0.5A(0), hence:

A(t) = A(0)(0.88)^t

0.5A(0) = A(0)(0.88)^t

(0.88)^t = 0.5

\log{(0.88)^t} = \log{0.5}

t\log{0.88} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.88}}

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

9 0
1 year ago
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