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3 years ago

What is the domain of this function?

Mathematics

2 answers:

kogti [31]3 years ago

6 0

$2x-14\geq0\\\\ 2x\geq14\\\\ x\geq7\\\\ D_f:x\in\langle7,\infty)$

Jobisdone [24]3 years ago

5 0

The square root function is only defined for non-negative arguments. So you must have

... 2x - 14 ≥ 0

... 2x ≥ 14

... x ≥ 7

In interval notation, x ∈ [7, ∞)

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Use the table to find the slope. -2 2 1/2 -1/2

Tresset [83]

Answer:

going upp then downn

Step-by-step explanation:

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2 years ago

ANSWER NOW HURRY

Annette [7]

The answer is C because it’s twice as long

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2 years ago

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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

Find the distance AB

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

Find the distance BC

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

Find the distance AC

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

Find the distance DC

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

Find the perimeter of the triangle

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

Find the area of the triangle

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

When we’re writing, we can use a thesaurus to find a different word with the same meaning to present an idea. How can we find di

Pavlova-9 [17]

Answer:

Math has the particularity that it is a logical construction.

This means that we can start with an expression X (where X is an equation, not a variable)

Now we can apply a lot of "math" to this equation in such a way that we can rewrite it, but the actual "meaning" of the equation will not change.

An example of this is factoring.

For example, we can write a quadratic equation as:

a*x^2 + b*x + c.

And we also can write this as:

n*(x - k)*(x - j)

where k and j are the solutions of the equation:

a*x^2 + b*x + c = 0.

What is the advantage of writing the equation in each form?

Well, both expressions actually represent the same thing, but the explicit information in each expression is different, so depending on what we want to do, we will choose one option or the other.

And we have lot's of different ways to express something, where we can find some ones really complex and useful, like the series of Taylor, where we can write a function as a summation of infinite terms.

8 0

2 years ago

Standard form of a line passing through points (1, 3) and (-2, 5)

____ [38]

Answer:

Step-by-step explanation:

As we move from (-2, 5) to (1, 3), x increases by 3 and y decreases by 2.

Hence, the slope of this line is m = rise / run = -2/3.

Start with the slope-intercept form y = mx + b.

Substitute 3 for y and 1 for x and -2/3 for m:

3 = (-2/3)(1) + b.

Remove fractions by mult. all three terms by 3:

9 = -2 + b, so b = 11, and y = (-2/3)x + 11

Again, mult. all three terms by 3:

3y = -2x + 33, or, in standard form,

6 0

3 years ago