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Scilla [17]
3 years ago
11

How do I do probabillty

Mathematics
2 answers:
zysi [14]3 years ago
4 0

Answer:

Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring. In the case of rolling a 3 on a die, the number of events is 1 (there's only a single 3 on each die), and the number of outcomes is 6.

diamong [38]3 years ago
4 0

Answer:

what the other guy said

Step-by-step explanation:

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Express the percent as a decimal.<br> 30\%30%30, percent<br> Stuck help
Marrrta [24]
If it’s 30% converted to a decimal it’ll be .30
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2 years ago
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Solve for n<br><br> -19=-8+n
laila [671]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{n = -11}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{-19 = -8 + n}

Find:  \textsf{Solve for n}

Solution: In order to solve for n we need to add 8 to both sides which would cancel -8 on the right side and isolate n giving us the value of n.

<u>Add 8 to both sides</u>

  • \textsf{-19 + 8 = -8 + 8 + n}
  • \textsf{-19 + 8 = n}
  • \textsf{-11 = n}

Therefore, the final answer would be that n is equal to -11.

6 0
1 year ago
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Find the coordinates of the point 13 of the way from A to B.
Travka [436]

Answer:

The answer is 0, 1/3.

Step-by-step explanation:

This is because only at 0 does the line intersect through 1/3.

4 0
2 years ago
Jason earns &amp;10.59 per hour. He works 5.75 hours Saturday how much money does he earn Saturday? I know the answer is $60.89
marin [14]
So you are rounding 60.89.
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4 0
3 years ago
a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di
Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}

Thus, the total prototypes will cost around $60.75

7 0
1 year ago
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