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3 years ago

10

Please help! Brainliest to the first answer!

1 answer:

Helga [31]3 years ago

3 0

She needs 4 more beads

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The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. F

omeli [17]

Answer:

Step-by-step explanation:

find the slope

$\frac{4-8}{-5-(-3)} =\frac{-4}{-2} \\\\slope=2\\y=mx+b\\y=2x+b\\$

take a coordinate to fill in

$(-5,4)\\y=-5\\x=4\\-5=2(4)+b\\-5=8+b-8 -8\\-13=b\\$

this means that the equation is y=2x-13

and if you add m and b

you get :-11

<u><em>I HOPE THIS HELPS</em></u>

8 0

3 years ago

Read 2 more answers

Please explain step by step

Alja [10]

Let's find the value of x

Since the sum of internal angles of a triangle is 180°

therefore,

$\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree$

$\hookrightarrow \: 2x - 2 \degree + x + 5\degree = 180\degree - 90\degree$

$\hookrightarrow \: 3x + 3\degree = 90\degree$

$\hookrightarrow \: 3(x + 1) = 3(30)$

$\hookrightarrow \: x + 1\degree = 30\degree$

$\hookrightarrow \: x = 29\degree$

4 0

3 years ago

18 divided by 6 multiples by 4-3 +6

yKpoI14uk [10]

15 is the answer i think

6 0

3 years ago

Write an equation in slope-intercept form for the line

Art [367]

Answer:

Step-by-step explanation:

y - 2 = -4(x - 1)

y - 2 = -4x + 4

y = -4x + 6

4 0

3 years ago

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

11111nata11111 [884]

Answer:

$R' = (-1,-0.5)$

Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

$R' = (4,5) * 0.5$

$R' = (4* 0.5,5* 0.5)$

$R' = (2,2.5)$

Lastly, measure R' from the origin by adding the coordinates of P to R'

$R' = (2+(-3),2.5+(-3))$

$R' = (2-3,2.5-3)$

$R' = (-1,-0.5)$

6 0

2 years ago